This problem involves finding the length of a chord within a circle given its radius and its distance from the center. We can visualize a right-angled triangle formed by:
Let the radius of the circle be r = 15 cm.
Let the distance of the chord from the center be d = 9 cm.
Let half the length of the chord be x. The full length of the chord will be 2x.
According to the Pythagorean theorem in the right-angled triangle:
$r^2 = d^2 + x^2$
Substitute the given values:
$15^2 = 9^2 + x^2$
$225 = 81 + x^2$
Solve for $x^2$:
$x^2 = 225 - 81$
$x^2 = 144$
Find the value of x:
$x = \sqrt{144}$
$x = 12 \text{ cm}$
The length of the chord is twice the value of x:
Chord Length = $2x$
Chord Length = $2 \times 12$ cm
Chord Length = 24 cm
The length of the chord is 24 cm.
In a circle, a ten cm long chord is at a distance of 12 cm from the centre of the circle. The length of the diameter of the circle (in cm) is:
Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?