The goal is to find the median weight from the given list of 7 men's weights.
First, arrange the weights in ascending order:
The median is the middle value in a sorted data set. Since there are 7 observations (an odd number), the median is the value at the middle position.
The position of the median is calculated using the formula:
Position = $\frac{n+1}{2}$
Where 'n' is the number of observations.
In this case, $n = 7$.
Position = $\frac{7+1}{2} = \frac{8}{2} = 4$
The median is the 4th value in the ordered list.
Looking at the ordered list (61, 62, 63, 64, 65, 66, 67), the 4th value is 64 kg.
Therefore, the median weight is 64 kg.
| Height (cm) | Number of persons |
|---|---|
| 120 | 3 |
| 130 | 4 |
| 140 | 5 |
| 150 | 6 |
| 160 | 2 |
| Value | 3 | 2 | k | 4 | 5 |
| Frequency | k | 2k | 3k | 4k | 5k |
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
What will be the difference between mean and median of the given data?
21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is