The given set is S = {1, 2, 2, 3, 3, 3, 4, 4, 4, 4}. The total number of elements is 10.
First, find the sum of all elements in the set:
Sum = $1 + 2 + 2 + 3 + 3 + 3 + 4 + 4 + 4 + 4 = 30$.
The mean is calculated by dividing the sum by the number of elements:
Mean = $\frac{\text{Sum of elements}}{\text{Number of elements}} = \frac{30}{10} = 3$.
The mode is the value that appears most frequently in the data set.
Count the frequency of each number in S:
The number 4 has the highest frequency (4 times). Therefore, the mode is 4.
The set S is already sorted: {1, 2, 2, 3, 3, 3, 4, 4, 4, 4}.
Since there are 10 elements (an even number), the median is the average of the two middle elements, which are the 5th and 6th elements.
The 5th element is 3.
The 6th element is 3.
Median = $\frac{5\text{th element} + 6\text{th element}}{2} = \frac{3 + 3}{2} = \frac{6}{2} = 3$.
Now substitute the calculated values of mean, mode, and median into the expression:
Expression = $4 \times (3) + 2 \times (4) - 8 \times (3)$
Perform the calculations:
Expression = $12 + 8 - 24$
Expression = $20 - 24 = -4$.
The value of the expression $4 \times \text{mean} + 2 \times \text{mode} - 8 \times \text{median}$ is -4.
| Height (cm) | Number of persons |
|---|---|
| 120 | 3 |
| 130 | 4 |
| 140 | 5 |
| 150 | 6 |
| 160 | 2 |
| Value | 3 | 2 | k | 4 | 5 |
| Frequency | k | 2k | 3k | 4k | 5k |
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
What will be the difference between mean and median of the given data?
21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is