80, 90, 40, 30, 20, 10, 70, 60, 50
To find the difference between the two medians, we first calculate the median of the original data and then the median of the data after the replacement.
The original data set is:
80, 90, 40, 30, 20, 10, 70, 60, 50
First, arrange the data in ascending order:
10, 20, 30, 40, 50, 60, 70, 80, 90
There are $n=9$ observations. The median is the middle value, which is the $(\frac{n+1}{2})^{th}$ term.
Median position = $(\frac{9+1}{2}) = 5^{th}$ term.
The 5th term in the sorted list is 50. So, the original median is 50.
Now, replace the number 30 with 100 in the original data set:
80, 90, 40, 100, 20, 10, 70, 60, 50
Arrange this new data set in ascending order:
10, 20, 40, 50, 60, 70, 80, 90, 100
The number of observations is still $n=9$. The median is again the $(\frac{n+1}{2})^{th}$ term.
Median position = $(\frac{9+1}{2}) = 5^{th}$ term.
The 5th term in this sorted list is 60. So, the new median is 60.
The question asks for the difference between the two medians.
Difference = (New Median) - (Original Median)
Difference = $60 - 50$
Difference = $10$
The difference between the two medians is 10.
| Height (cm) | Number of persons |
|---|---|
| 120 | 3 |
| 130 | 4 |
| 140 | 5 |
| 150 | 6 |
| 160 | 2 |
| Value | 3 | 2 | k | 4 | 5 |
| Frequency | k | 2k | 3k | 4k | 5k |
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
What will be the difference between mean and median of the given data?
21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is