This problem requires us to find the total surface area of a cube when we know its volume. We need to use the relationship between a cube's volume, its side length, and its total surface area.
A cube is a three-dimensional shape with six equal square faces. All its edges (sides) have the same length.
We are given that the volume of the cube is 64 cm³. We can use the volume formula to find the side length '$s$'.
Given:
$V = 64 \text{ cm}^3$Using the formula $V = s^3$:
$s^3 = 64 \text{ cm}^3$To find '$s$', we need to take the cube root of 64:
$s = \sqrt[3]{64 \text{ cm}^3}$ $s = 4 \text{ cm}$So, the length of each side of the cube is 4 cm.
Now that we know the side length ('$s = 4$ cm'), we can calculate the total surface area using the formula $TSA = 6s^2$.
Calculation:
$TSA = 6 \times (4 \text{ cm})^2$ $TSA = 6 \times (16 \text{ cm}^2)$ $TSA = 96 \text{ cm}^2$The total surface area of the cube is 96 cm².
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