The question asks us to find the surface area of a ball (which is a sphere) given its radius. We are also provided with a specific value to use for pi ($\pi$).
To calculate the surface area of a sphere, we use the standard mathematical formula:
$$A = 4 \pi r^2$$
Where:
Now, let's substitute the given values into the formula:
$$A = 4 \times \frac{22}{7} \times (21 \text{ mm})^2$$
$$(21 \text{ mm})^2 = 21 \times 21 \text{ mm}^2 = 441 \text{ mm}^2$$
$$A = 4 \times \frac{22}{7} \times 441 \text{ mm}^2$$
$$A = 4 \times \frac{22}{7} \times 21 \times 21 \text{ mm}^2$$
$$A = 4 \times 22 \times \frac{21}{7} \times 21 \text{ mm}^2$$
$$A = 4 \times 22 \times 3 \times 21 \text{ mm}^2$$
$$A = 88 \times 63 \text{ mm}^2$$
Let's calculate $88 \times 63$:
$88 \times 60 = 5280$
$88 \times 3 = 264$
$5280 + 264 = 5544$
Therefore,
$$A = 5544 \text{ mm}^2$$
The calculated surface area is $5544 \text{ mm}^2$. Comparing this result with the given options, we find that it matches one of the choices.
Result: The surface area of the ball is $5544 \text{ mm}^2$.
In a circular garden of radius 15 m, a path of 2 m wide has to be made inside the garden at the rate of ₹ 24 per sq. m. The cost of making the path is: (Take π = \(\frac{22}{7}\) )
A hollow cylinder with outer radius 4 cm and height 2 cm is made up of 1 cm thick metal sheet. What is the volume of metal used? (Take π = \(\frac{22}{7}\))
The length and breadth of a rectangular field are in the ratio 4 : 3. If the cost of cultivating the field at ₹2 per m 2is ₹600, then the length of the field is:
A cylindrical tank has a capacity of 5632 m3. If the diameter of its base is 8 m, what is the depth of the cylindrical tank? (Use π = \(\frac{22}{7}\))
Find the surface area of a sphere whose diameter is equal to 28 cm.