This problem asks us to find the side length of a square whose area is the same as a given rectangle. We are provided with the rectangle's perimeter and the difference between its length and width.
Let's denote the length of the rectangle as '$l$' and the width as '$w$'.
So, the dimensions of the rectangle are 90 m and 50 m.
The area of a rectangle is calculated by multiplying its length and width ($A = l \times w$). Using the dimensions we found:
$$A_{\text{rectangle}} = 90 \text{ m} \times 50 \text{ m}$$ $$A_{\text{rectangle}} = 4500 \text{ m}^2$$The problem states that the area of a square is equal to the area of this rectangle. Let the side length of the square be '$s$'. The area of a square is given by $A_{\text{square}} = s^2$. Therefore:
$$s^2 = A_{\text{rectangle}}$$ $$s^2 = 4500 \text{ m}^2$$To find the side length '$s$', we need to take the square root of the area:
$$s = \sqrt{4500 \text{ m}^2}$$Now, let's simplify the square root:
$$s = \sqrt{45 \times 100} \text{ m}$$ $$s = \sqrt{9 \times 5 \times 100} \text{ m}$$We can take the square root of the perfect squares (9 and 100):
$$s = \sqrt{9} \times \sqrt{5} \times \sqrt{100} \text{ m}$$ $$s = 3 \times \sqrt{5} \times 10 \text{ m}$$ $$s = 30\sqrt{5} \text{ m}$$The side of the square whose area is equal to the area of the rectangle is $30\sqrt{5}$ m.
A hemispherical bowl has a 21 cm radius. It is to be painted inside as well as outside. The cost of painting it at the rate of ₹0.05 per $cm^2$ and assuming that the thickness of the bowl is negligible, is: (Use $\pi = \frac{22}{7}$)
A solid cube is painted yellow, blue and black such that opposite faces are of same colour. The cube is then cut into 36 cubes of two different sizes such that 32 cubes are small and the other four cubes are Big. None of the faces of the bigger cubes is painted blue. How many cubes have only one face painted?
A and B are two heavy steel blocks. If B is placed on the top of A, the weight increases by 60%. How much weight will reduce with respect to the total weight of A and B, if B is removed from the top of A?
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The centroid of an equilateral triangle ABC is G. If AB is 6 cms, the length of AG is