The value of the determinant \(\left| {\begin{array}{*{20}{c}} {1 - {\rm{\alpha }}}&{{\rm{\alpha }} - {{\rm{\alpha }}^2}}&{{{\rm{\alpha }}^2}}\\ {1 - {\rm{\beta }}}&{{\rm{\beta }} - {{\rm{\beta }}^2}}&{{{\rm{\beta }}^2}}\\ {1 - {\rm{\gamma }}}&{{\rm{\gamma }} - {{\rm{\gamma }}^2}}&{{{\rm{\gamma }}^2}} \end{array}} \right|\) is equal to
(α - β)(β - γ)(γ - α)
We are asked to find the value of the given determinant:
\[ \Delta = \left| {\begin{array}{*{20}{c}} {1 - {\rm{\alpha }}}&{{\rm{\alpha }} - {{\rm{\alpha }}^2}}&{{{\rm{\alpha }}^2}}\\ {1 - {\rm{\beta }}}&{{\rm{\beta }} - {{\rm{\beta }}^2}}&{{{\rm{\beta }}^2}}\\ {1 - {\rm{\gamma }}}&{{\rm{\gamma }} - {{\rm{\gamma }}^2}}&{{{\rm{\gamma }}^2}} \end{array}} \right| \]Let's simplify the determinant using elementary column operations. Recall that the value of a determinant does not change if we add a multiple of one column to another column.
First, observe the second column. We can factor out \(\alpha\), \(\beta\), and \(\gamma\) from the respective elements:
\[ \alpha - \alpha^2 = \alpha(1 - \alpha) \] \[ \beta - \beta^2 = \beta(1 - \beta) \] \[ \gamma - \gamma^2 = \gamma(1 - \gamma) \]So the determinant can be written as:
\[ \Delta = \left| {\begin{array}{*{20}{c}} {1 - {\rm{\alpha }}}&{{\rm{\alpha }}(1 - {\rm{\alpha }})}&{{{\rm{\alpha }}^2}}\\ {1 - {\rm{\beta }}}&{{\rm{\beta }}(1 - {\rm{\beta }})}&{{{\rm{\beta }}^2}}\\ {1 - {\rm{\gamma }}}&{{\rm{\gamma }}(1 - {\rm{\gamma }})}&{{{\rm{\gamma }}^2}} \end{array}} \right| \]Let \(C_1\), \(C_2\), and \(C_3\) denote the first, second, and third columns, respectively.
Perform the operation \(C_2 \leftarrow C_2 + C_3\). This means we add the elements of the third column to the corresponding elements of the second column.
The determinant becomes:
| \(1 - {\rm{\alpha }}\) | \({\rm{\alpha }}\) | \({\rm{\alpha }}^2\) |
| \(1 - {\rm{\beta }}\) | \({\rm{\beta }}\) | \({\rm{\beta }}^2\) |
| \(1 - {\rm{\gamma }}\) | \({\rm{\gamma }}\) | \({\rm{\gamma }}^2\) |
Now, perform the operation \(C_1 \leftarrow C_1 + C_2\). This means we add the elements of the second column to the corresponding elements of the first column.
The determinant simplifies to:
| \(1\) | \({\rm{\alpha }}\) | \({\rm{\alpha }}^2\) |
| \(1\) | \({\rm{\beta }}\) | \({\rm{\beta }}^2\) |
| \(1\) | \({\rm{\gamma }}\) | \({\rm{\gamma }}^2\) |
This simplified determinant is a standard form known as a Vandermonde determinant. A Vandermonde determinant of order 3 is given by:
\[ \left| {\begin{array}{*{20}{c}} 1&a&a^2\\ 1&b&b^2\\ 1&c&c^2 \end{array}} \right| = (b-a)(c-a)(c-b) \]Comparing our determinant with the Vandermonde form, we have \(a = \alpha\), \(b = \beta\), and \(c = \gamma\).
Using the formula, the value of our determinant is:
\[ (\beta - \alpha)(\gamma - \alpha)(\gamma - \beta) \]We can rearrange the terms and factors to match the given options. Recall that \((x-y) = -(y-x)\).
\[ (\beta - \alpha) = -(\alpha - \beta) \] \[ (\gamma - \beta) = -(\beta - \gamma) \] \[ (\gamma - \alpha) = (\gamma - \alpha) \]So, the determinant value is:
\[ (-(\alpha - \beta)) \cdot (\gamma - \alpha) \cdot (-(\beta - \gamma)) \] \[ = (-1)(-1) (\alpha - \beta)(\gamma - \alpha)(\beta - \gamma) \] \[ = (\alpha - \beta)(\beta - \gamma)(\gamma - \alpha) \]This matches Option 2.
| Step | Operation/Concept | Result/Purpose |
|---|---|---|
| 1 | Identify the determinant structure | Recognize the pattern in rows involving \(\alpha, \beta, \gamma\). |
| 2 | Apply \(C_2 \leftarrow C_2 + C_3\) | Simplify the second column elements from \(x(1-x)\) to \(x\). |
| 3 | Apply \(C_1 \leftarrow C_1 + C_2\) | Simplify the first column elements from \(1-x\) to \(1\). |
| 4 | Identify Vandermonde form | Recognize the resulting matrix structure \(\begin{pmatrix} 1 & x & x^2 \\ 1 & y & y^2 \\ 1 & z & z^2 \end{pmatrix}\). |
| 5 | Apply Vandermonde formula | Calculate the determinant value using the known formula. |
| 6 | Simplify and Match | Rearrange factors and signs to match the given options. |
A Vandermonde determinant is a determinant of a matrix where the entries of each row are powers of a sequence of elements, such as \(a^0, a^1, a^2, \ldots, a^{n-1}\). For an \(n \times n\) matrix, the Vandermonde determinant with elements \(a_1, a_2, \ldots, a_n\) is given by:
\[ \left| {\begin{array}{*{20}{c}} 1&a_1&a_1^2& \cdots &a_1^{n-1}\\ 1&a_2&a_2^2& \cdots &a_2^{n-1}\\ \vdots & \vdots & \vdots & \ddots & \vdots \\ 1&a_n&a_n^2& \cdots &a_n^{n-1}} \end{array}} \right| = \prod_{1 \le i < j \le n} (a_j - a_i) \]For a 3x3 matrix with elements \(a, b, c\), the product is \((a_2-a_1)(a_3-a_1)(a_3-a_2)\), which corresponds to \((b-a)(c-a)(c-b)\) when \(a_1=a, a_2=b, a_3=c\).
Vandermonde determinants are important in polynomial interpolation and other areas of linear algebra.
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