The element in the i th row and the j th column of a determinant of third order is equal to 2(i + j). What is the value of the determinant?
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The question asks for the value of a determinant of the third order. The element in the i-th row and j-th column, denoted by \(a_{ij}\), is given by the formula \(a_{ij} = 2(i+j)\).
A third-order determinant has 3 rows and 3 columns. We can find each element using the given formula:
So, the determinant is:
\[ \begin{vmatrix} 4 & 6 & 8 \\ 6 & 8 & 10 \\ 8 & 10 & 12 \end{vmatrix} \]
There are several ways to evaluate this determinant. We can expand it, or we can use properties of determinants. Let's look at the relationships between the rows:
Observe the difference between consecutive rows:
Since the difference between consecutive rows is constant, the rows of the determinant are in Arithmetic Progression (AP).
A fundamental property of determinants states that if the rows (or columns) of a determinant are in Arithmetic Progression, the value of the determinant is zero.
Alternatively, we can use row operations to simplify the determinant. Let R1, R2, and R3 denote the first, second, and third rows, respectively.
Apply the operation \(R_2 \to R_2 - R_1\):
\[ \begin{vmatrix} 4 & 6 & 8 \\ 6-4 & 8-6 & 10-8 \\ 8 & 10 & 12 \end{vmatrix} = \begin{vmatrix} 4 & 6 & 8 \\ 2 & 2 & 2 \\ 8 & 10 & 12 \end{vmatrix} \]
Apply the operation \(R_3 \to R_3 - R_1\):
\[ \begin{vmatrix} 4 & 6 & 8 \\ 2 & 2 & 2 \\ 8-4 & 10-6 & 12-8 \end{vmatrix} = \begin{vmatrix} 4 & 6 & 8 \\ 2 & 2 & 2 \\ 4 & 4 & 4 \end{vmatrix} \]
Now observe the relationship between the second row \(R_2 = (2, 2, 2)\) and the third row \(R_3 = (4, 4, 4)\). We can see that \(R_3 = 2 \times R_2\).
Another property of determinants states that if one row (or column) is a scalar multiple of another row (or column), the value of the determinant is zero.
Since \(R_3\) is a multiple of \(R_2\), the value of the determinant is 0.
Using either the property of rows in AP or row operations revealing dependent rows, we find that the value of the determinant is 0.
| Element | Formula \(a_{ij} = 2(i+j)\) | Value |
|---|---|---|
| \(a_{11}\) | 2(1+1) | 4 |
| \(a_{12}\) | 2(1+2) | 6 |
| \(a_{13}\) | 2(1+3) | 8 |
| \(a_{21}\) | 2(2+1) | 6 |
| \(a_{22}\) | 2(2+2) | 8 |
| \(a_{23}\) | 2(2+3) | 10 |
| \(a_{31}\) | 2(3+1) | 8 |
| \(a_{32}\) | 2(3+2) | 10 |
| \(a_{33}\) | 2(3+3) | 12 |
| Concept | Description | Relevance to Problem |
|---|---|---|
| Third Order Determinant | A square array of numbers (3x3) whose value is calculated by a specific rule. | The problem involves calculating the value of a 3x3 determinant. |
| Element \(a_{ij}\) | The number in the i-th row and j-th column of the determinant/matrix. | The elements are defined by the formula \(a_{ij} = 2(i+j)\). |
| Determinant with Rows/Columns in AP | If rows or columns form an Arithmetic Progression (constant difference between consecutive rows/columns), the determinant value is zero. | The rows (and columns) of the calculated determinant are in AP. |
| Determinant with Linearly Dependent Rows/Columns | If one row/column can be expressed as a linear combination of other rows/columns (e.g., one row is a multiple of another), the determinant value is zero. | Row operations showed \(R_3 = 2 R_2\), indicating linear dependence. |
Understanding the properties of determinants is crucial for solving many linear algebra problems quickly. Some key properties include:
Recognizing patterns like rows/columns in Arithmetic Progression or linear dependency can significantly simplify the calculation of determinants.
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