The value of \(\left(2+\dfrac32\right)^2 - \left[4-\left(\dfrac63\right)^2\right] \div \dfrac12\) is
\(\tfrac{49}{2}\)
\(\left(2+\dfrac32\right)^2 = \left(\dfrac72\right)^2 = \dfrac{49}{4}\).
\(\left(\dfrac63\right)^2 = 2^2 = 4\), so the bracket \(4-4=0\).
The whole expression, taken together, is then divided by \(\tfrac12\): \(\dfrac{49}{4}\div\dfrac12 = \dfrac{49}{4}\times2 = \dfrac{49}{2}\).
Hence, the value of the expression is \(\tfrac{49}{2}\).
Simplify the given expression using BODMAS.
$\frac{4}{11} \times \frac{121}{16} \times 24 (75^2 - 55^2) \times \frac{1}{100}$
The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:
The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:
The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:
The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:
The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is: