The value of \(\left(2+\dfrac32\right)^2 - \left[4-\left(\dfrac63\right)^2\right] \div \dfrac12\) is
\(\tfrac{49}{2}\)
\(\left(2+\dfrac32\right)^2 = \left(\dfrac72\right)^2 = \dfrac{49}{4}\).
\(\left(\dfrac63\right)^2 = 2^2 = 4\), so the bracket \(4-4=0\).
The whole expression, taken together, is then divided by \(\tfrac12\): \(\dfrac{49}{4}\div\dfrac12 = \dfrac{49}{4}\times2 = \dfrac{49}{2}\).
Hence, the value of the expression is \(\tfrac{49}{2}\).
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Important Questions from Bodmas Rule
If 2945 ÷ 19 – 11 × 5 = 29 + a, find the value of a.
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3800 - 22 × 1968 ÷ 48 = ? × 7
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What will come in the place of question mark (?) in the given expression?
(420 ÷ 12 × 35 + 452- 152) = ?2
Evaluate: (13 × 8 - √81 × 6 + 1 ) ÷ (√49 + 72 - 18 × 2 + 19)
