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Question

Using BODMAS, simplify the following.
$\frac{7}{9} \times \frac{21}{5} \times 25 (65^2 - 55^2)$

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
98000

Simplifying Expression Using BODMAS Rule

The problem requires simplifying the expression $\frac{7}{9} \times \frac{21}{5} \times 25 (65^2 - 55^2)$ using the BODMAS rule.

BODMAS stands for: Bracket, Orders (powers/roots), Division, Multiplication, Addition, Subtraction.

Step-by-Step Simplification

Step 1: Simplify the expression within the brackets (Orders).

Calculate the term involving powers and subtraction: $(65^2 - 55^2)$.

Using the difference of squares formula, $a^2 - b^2 = (a-b)(a+b)$:

$65^2 - 55^2 = (65 - 55)(65 + 55)$

$= (10)(120)$

$= 1200$

Step 2: Substitute the bracket result back into the expression.

The expression becomes:

$\frac{7}{9} \times \frac{21}{5} \times 25 \times 1200$

Step 3: Perform Multiplication from left to right.

First, multiply the fractions:

$\frac{7}{9} \times \frac{21}{5} = \frac{7 \times 21}{9 \times 5}$

Simplify by dividing 21 and 9 by their common factor 3:

$= \frac{7 \times (3 \times 7)}{(3 \times 3) \times 5} = \frac{7 \times 7}{3 \times 5} = \frac{49}{15}$

The expression is now:

$\frac{49}{15} \times 25 \times 1200$

Next, multiply $\frac{49}{15}$ by 25:

$\frac{49}{15} \times 25 = \frac{49 \times 25}{15}$

Simplify by dividing 25 and 15 by their common factor 5:

$= \frac{49 \times (5 \times 5)}{(3 \times 5)} = \frac{49 \times 5}{3} = \frac{245}{3}$

The expression is now:

$\frac{245}{3} \times 1200$

Finally, multiply $\frac{245}{3}$ by 1200:

$\frac{245}{3} \times 1200 = 245 \times \frac{1200}{3}$

Simplify by dividing 1200 by 3:

$= 245 \times 400$

Step 4: Calculate the final product.

$245 \times 400 = 98000$

Final Answer

The simplified value of the expression is 98000.

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Important Questions from Bodmas Rule

  1. The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:

  2. The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:

  3. The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:

  4. The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:

  5. The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:

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