$\frac{7}{9} \times \frac{21}{5} \times 25 (65^2 - 55^2)$
The problem requires simplifying the expression $\frac{7}{9} \times \frac{21}{5} \times 25 (65^2 - 55^2)$ using the BODMAS rule.
BODMAS stands for: Bracket, Orders (powers/roots), Division, Multiplication, Addition, Subtraction.
Step 1: Simplify the expression within the brackets (Orders).
Calculate the term involving powers and subtraction: $(65^2 - 55^2)$.
Using the difference of squares formula, $a^2 - b^2 = (a-b)(a+b)$:
$65^2 - 55^2 = (65 - 55)(65 + 55)$
$= (10)(120)$
$= 1200$
Step 2: Substitute the bracket result back into the expression.
The expression becomes:
$\frac{7}{9} \times \frac{21}{5} \times 25 \times 1200$
Step 3: Perform Multiplication from left to right.
First, multiply the fractions:
$\frac{7}{9} \times \frac{21}{5} = \frac{7 \times 21}{9 \times 5}$
Simplify by dividing 21 and 9 by their common factor 3:
$= \frac{7 \times (3 \times 7)}{(3 \times 3) \times 5} = \frac{7 \times 7}{3 \times 5} = \frac{49}{15}$
The expression is now:
$\frac{49}{15} \times 25 \times 1200$
Next, multiply $\frac{49}{15}$ by 25:
$\frac{49}{15} \times 25 = \frac{49 \times 25}{15}$
Simplify by dividing 25 and 15 by their common factor 5:
$= \frac{49 \times (5 \times 5)}{(3 \times 5)} = \frac{49 \times 5}{3} = \frac{245}{3}$
The expression is now:
$\frac{245}{3} \times 1200$
Finally, multiply $\frac{245}{3}$ by 1200:
$\frac{245}{3} \times 1200 = 245 \times \frac{1200}{3}$
Simplify by dividing 1200 by 3:
$= 245 \times 400$
Step 4: Calculate the final product.
$245 \times 400 = 98000$
The simplified value of the expression is 98000.
What will the value of the following expression be?
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