The value of cosec 41° - sec 49° is:
0
The correct answer is 0.
Simplify the Expression: Try to rewrite the expression using identities to make it simpler or to cancel terms out. Convert to Sine and Cosine: Sometimes, writing all terms in terms of sine and cosine can help in simplification. In this specific problem, recognizing that $41^\circ$ and $49^\circ$ are complementary angles and applying the $\text{cosec}/\text{sec}$ identity was the key to quickly finding the value of the expression.
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
The value of cot (-315°) is :
The value of \(\frac{\tan^2 (22^\circ - \theta)-\tan (\theta + 68^\circ)\ -\ \text{cosec}^2 (68^\circ + \theta)+\cot (22^\circ - \theta)} {3 (\cot^2 52^\circ - \sec^2 38^\circ)+ 2 (\text{cosec}^2 \ 28^\circ - \tan^2 62^\circ)}\) is:
The value of \(\frac{{{{\sec }^2}60^\circ {{\cos }^2}45^\circ \, + \,{\rm{cose}}{{\rm{c}}^2}30^\circ }}{{{{\sec }^2}45^\circ - \tan 45^\circ }}\) is:
The value of \(\sin^2\frac{2\pi}{3}+\cos^2\frac{5\pi}{6}-\tan^2\frac{3\pi}{4}\) is :
sinθ + cosec θ = 2, then the value of sin 99 θ + cosec 99 θ is:
If cos θ = \(\frac{5}{13}\) , what is the value of cot θ ?
Determine the largest angle if the angles of a triangle are in the ratio 3 : 4 : 5.
The value of the expression \(\rm \frac{4\sin^230^{\circ}+\cos^260^{\circ}-\tan^245^{\circ}}{2\sin60^{\circ}\cos30^{\circ}-\tan45^{\circ}}\) is:
If tan 15θ = cot 15θ (0° < θ < 10°) , then the value of θ is:
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
1 + tan 15° cot 75° is equal to:
The value of cot (-315°) is :
θ = 135°; γ = 15°.
What is the value of 2 cos(θ) sin(γ)?
If tan(90 – θ) = \(\frac{2}{\sqrt3}\), then the value of \(2\sqrt3\) tan θ + 1 is: