The value of \(\frac{\tan^2 (22^\circ - \theta)-\tan (\theta + 68^\circ)\ -\ \text{cosec}^2 (68^\circ + \theta)+\cot (22^\circ - \theta)} {3 (\cot^2 52^\circ - \sec^2 38^\circ)+ 2 (\text{cosec}^2 \ 28^\circ - \tan^2 62^\circ)}\) is:
1
The correct answer is 1.
Tangent of one angle is the cotangent of its complement. Secant of one angle is the cosecant of its complement. These identities allow us to rewrite trigonometric functions of angles greater than 45^\circ in terms of angles less than 45^\circ , which can sometimes make calculations or comparisons easier. In problems like this, recognizing complementary angles helps simplify complex expressions by converting terms into functions of the same angle.
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
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sinθ + cosec θ = 2, then the value of sin 99 θ + cosec 99 θ is:
If cos θ = \(\frac{5}{13}\) , what is the value of cot θ ?
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The value of the expression \(\rm \frac{4\sin^230^{\circ}+\cos^260^{\circ}-\tan^245^{\circ}}{2\sin60^{\circ}\cos30^{\circ}-\tan45^{\circ}}\) is:
The general solution of the equation \(\tan 3x + \cot (2x + \frac{\pi }{3}) = 0\) is:
If tan 15θ = cot 15θ (0° < θ < 10°) , then the value of θ is:
Which of the following values of A and B satisfies, sin(A + B) = sin A + sin B, where
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
The value of 4cos\(\left( {\frac{\pi }{6}\, - \,\alpha } \right)\) sin\(\left( {\frac{\pi }{3}\, - \,\alpha } \right)\) is equal to:
1 + tan 15° cot 75° is equal to:
If tan θ = 1/√5, find the value of cosec2θ – sec2θ.