If tan 15θ = cot 15θ (0° < θ < 10°) , then the value of θ is:
3°
The correct answer is 3°.
Given the options, and the common practice in exams, the value derived from the $45^\circ$ case is often the expected answer. Final Answer Determination The value $\theta = 3^\circ$ satisfies the equation $\tan(15\theta) = \cot(15\theta)$ because $\tan(15 \times 3^\circ) = \tan(45^\circ) = 1$ and $\cot(15 \times 3^\circ) = \cot(45^\circ) = 1$. Furthermore, $3^\circ$ is within the specified range $0^\circ < \theta < 10^\circ$. This corresponds to one of the provided options.
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