The value of \(\frac{{{{\sec }^2}60^\circ {{\cos }^2}45^\circ \, + \,{\rm{cose}}{{\rm{c}}^2}30^\circ }}{{{{\sec }^2}45^\circ - \tan 45^\circ }}\) is:
6
The correct answer is 6.
This is why {\rm{cose}}{{\rm{c}}} 30^\circ = \frac{1}{{\sin 30^\circ}} = \frac{1}{{1/2}} = 2. Cotangent (\cot \theta) is the reciprocal of tangent (\tan \theta): \cot \theta = \frac{1}{{\tan \theta}}. Also, \cot \theta = \frac{{\cos \theta}}{{\sin \theta}}. Knowing these identities and the standard values is crucial for solving trigonometry problems like this one.
Similar Questions
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