The table given below shows the number of players participating in two games in six different schools? What is the ratio of total number of players participating in game A to the total number of players participating in game B?Games Schools A B J 31 58 K 24 36 L 18 26 M 29 37 N 12 33 P 40 44
77 ∶ 117
The question asks for the ratio of the total number of players participating in Game A to the total number of players participating in Game B across six different schools. We are given a table showing the number of players from each school in both games.
Let's look at the data provided in the table:
| Schools | Game A | Game B |
|---|---|---|
| J | 31 | 58 |
| K | 24 | 36 |
| L | 18 | 26 |
| M | 29 | 37 |
| N | 12 | 33 |
| P | 40 | 44 |
To find the ratio of the total number of players in Game A to the total number of players in Game B, we first need to sum up the players for each game across all schools.
Total players in Game A:
Sum the players from Game A column for schools J, K, L, M, N, and P.
\( \text{Total A} = 31 + 24 + 18 + 29 + 12 + 40 \)
Let's add these numbers:
So, the total number of players participating in Game A across all schools is \( 154 \).
Total players in Game B:
Sum the players from Game B column for schools J, K, L, M, N, and P.
\( \text{Total B} = 58 + 36 + 26 + 37 + 33 + 44 \)
Let's add these numbers:
So, the total number of players participating in Game B across all schools is \( 234 \).
The question asks for the ratio of the total number of players in Game A to the total number of players in Game B.
Ratio \( = \text{Total A} : \text{Total B} \)
Ratio \( = 154 : 234 \)
Now, we need to simplify this ratio. Both 154 and 234 are even numbers, so they are divisible by 2.
\( 154 \div 2 = 77 \)
\( 234 \div 2 = 117 \)
So, the simplified ratio is \( 77 : 117 \).
Let's check if 77 and 117 have any common factors. 77 is \( 7 \times 11 \). 117 is not divisible by 7 or 11. It is divisible by 3 (\( 1+1+7=9 \), which is divisible by 3). \( 117 \div 3 = 39 \). So, \( 117 = 3 \times 39 = 3 \times 3 \times 13 \). Since 77 and 117 have no common factors other than 1, the ratio \( 77 : 117 \) is in its simplest form.
The ratio of the total number of players participating in Game A to the total number of players participating in Game B is \( 77 : 117 \).
Here is a summary of the total players in each game:
| Game | Total Players |
|---|---|
| Game A | 154 |
| Game B | 234 |
| Ratio (A:B) | 154 : 234 or 77 : 117 (Simplified) |
A ratio is a way to compare two quantities. It shows how many times one quantity is contained in another or how the two quantities relate to each other. Ratios can be written with a colon (e.g., A:B), as a fraction (\( \frac{A}{B} \)), or with the word "to" (A to B).
To simplify a ratio, you divide both parts of the ratio by their greatest common divisor (GCD). This is similar to simplifying a fraction. In this case, the GCD of 154 and 234 is 2.
Ratios are dimensionless quantities, meaning they do not have units. They are widely used in various fields, including mathematics, science, and everyday life, to express relationships between numbers.
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2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
A = Total number of cars manufactured by all the companies.
K = Difference between the number of C3 type cars manufactured by company H and the number of B3 type bike manufactured by company E.
What is the value of A : K?
H = Total number of B2 type bike manufactured by all the companies.
R = Total number of C1 type car manufactured by company F, G and D together.
What is the value of H / R?
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What is the average of the total number of cars of type C1 manufactured by the given 5 companies?
Total number of bikes manufactured by company D is what percentage of total number of cars of type C1 manufacture by company G?
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Percentage of marks obtained by six students in five subjects A, B, C, D & E.
Students | Subject | ||||
A (out of 75) | B (out of 80) | C (out of 100) | D (out of 50) | E (out of 150) | |
Manju | 68 | 85 | 86 | 72 | 92 |
Amit | 64 | 65 | 80 | 96 | 80 |
Rekha | 88 | 75 | 65 | 74 | 90 |
Anuj | 80 | 55 | 68 | 66 | 84 |
Abhi | 72 | 65 | 72 | 54 | 74 |
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Table shows the number of trees planted in 4 cities from 2016 to 2020.
Years | Chandigarh | Ahmadabad | Pune | Kolkata |
2016 | 1800 | 2500 | 1800 | 2000 |
2017 | 2500 | 2300 | 1850 | 1800 |
2018 | 2300 | 2400 | 1840 | 1760 |
2019 | 2440 | 1950 | 1900 | 1600 |
2020 | 2250 | 2100 | 2000 | 1750 |
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Number of student Appeared (A) and Passed (P) in an annual examination from schools Q, R, S & T in five years (2014 to 2018)
Year | Schools | |||||||
Q | R | S | T | |||||
A | P | A | P | A | P | A | P | |
2014 | 320 | 240 | 400 | 340 | 420 | 273 | 250 | 225 |
2015 | 400 | 320 | 380 | 285 | 350 | 280 | 300 | 228 |
2016 | 440 | 286 | 360 | 288 | 330 | 264 | 320 | 256 |
2017 | 350 | 252 | 420 | 294 | 380 | 247 | 350 | 315 |
2018 | 375 | 320 | 450 | 405 | 400 | 344 | 375 | 300 |
The table shows the daily income (in Rs.) of 50 persons.
Study the table and answer the question:
Income (Rs) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
How many persons earn Rs. 200 or more but less than Rs. 300?
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