The sum of two positive numbers is 77 and their product is 1392. The positive difference between them is:
19
Let the two numbers be \(a\) and \(b\) with \(a + b = 77\) and \(ab = 1392\).
Use the identity \((a - b)^2 = (a + b)^2 - 4ab\).
Substitute: \((a - b)^2 = 77^2 - 4 \times 1392 = 5929 - 5568 = 361\).
Taking the positive square root, \(a - b = \sqrt{361} = 19\).
Hence, the positive difference between the two numbers is \(19\).
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 26x + 165 = 0
II. y2 – 38y + 357 = 0
Factorize the following:
(x 2- 6xy + 9y 2) - 25
If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that
AP = PQ = QB, then the mid point of PQ is
If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?
If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).