The sum of two positive numbers is 26 and their product is 144. The positive difference between them is:
10
Let the two positive numbers be \(a\) and \(b\) with \(a+b=26\) and \(ab=144\).
Use the identity \((a-b)^2=(a+b)^2-4ab\).
Substitute: \((a-b)^2 = 26^2 - 4\times 144 = 676 - 576 = 100\).
Therefore \(|a-b| = \sqrt{100} = 10\).
Hence, the positive difference between the two numbers is 10.
If 2x – y = 2 and xy = \(\frac{3}{2}\) , then what is the value of x 3– \(\frac{{{y^3}}}{8}\) ?
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The value of:
\(\frac{{\sin 23^\circ \cos 67^\circ + \sec52^\circ \sin38^\circ + \cos 23^\circ \sin 67^\circ + \rm cosec52^\circ \cos 38^\circ }}{{\rm cose{c^2}20^\circ - {{\tan }^2}70^\circ }}\)
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