The sum of two positive numbers is 26 and their product is 144. The positive difference between them is:
10
Let the two positive numbers be \(a\) and \(b\) with \(a+b=26\) and \(ab=144\).
Use the identity \((a-b)^2=(a+b)^2-4ab\).
Substitute: \((a-b)^2 = 26^2 - 4\times 144 = 676 - 576 = 100\).
Therefore \(|a-b| = \sqrt{100} = 10\).
Hence, the positive difference between the two numbers is 10.
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Important Questions from Algebra
The difference between the two positive numbers x and y where x > y, is 25% of x. If the value of y is 15, then the value of x is:
If p2 + q2 - r2 = 0, then the value of (p6 + q6 - r6) ÷ p2q2r2 is:
If √2 + √x = √3, then the value of x is equal to:
The sum of two numbers is 20 and their difference is 2.5. Ratio of these numbers will be:
If \(\rm \frac{\sqrt{19 - x \sqrt{12}}}{1} = \sqrt 4 - \sqrt 3\) then the value of x is equal to:
