The sum of two numbers is 20 and their product is 91. What should be the sum of their reciprocals?
A.13/7
B.20/91
C.91/20
D.13/20
B
This question tests the standard Algebra concept and its direct application to the stated values.
The given quantities are substituted into the standard formula or relation, and the expression is simplified step by step following BODMAS/identity rules.
Carrying out the calculation yields the required value: 20/91.
Hence, the correct answer is 20/91.
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 26x + 165 = 0
II. y2 – 38y + 357 = 0
Factorize the following:
(x 2- 6xy + 9y 2) - 25
If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that
AP = PQ = QB, then the mid point of PQ is
If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?
If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).