The smallest fraction, which should be added to the sum of \(2\frac{1}{2},\;3\frac{1}{3},\;4\frac{1}{4}\;and\;5\frac{1}{5}\) to make the result a whole number is:
43/60
The problem asks us to find the smallest fraction that, when added to the sum of the given mixed numbers \(2\frac{1}{2}\), \(3\frac{1}{3}\), \(4\frac{1}{4}\), and \(5\frac{1}{5}\), results in a whole number.
First, let's calculate the sum of the four given mixed numbers. We can separate the whole number parts and the fractional parts.
To add the fractional parts, we need to find a common denominator. The least common multiple (LCM) of the denominators 2, 3, 4, and 5 is 60.
Now, we convert each fraction to an equivalent fraction with a denominator of 60:
Now, add the equivalent fractions:
\(\frac{30}{60} + \frac{20}{60} + \frac{15}{60} + \frac{12}{60} = \frac{30 + 20 + 15 + 12}{60} = \frac{77}{60}\)
The total sum of the four mixed numbers is the sum of the whole parts plus the sum of the fractional parts:
\(\text{Total Sum} = 14 + \frac{77}{60}\)
The fractional part \(\frac{77}{60}\) is an improper fraction. Let's convert it to a mixed number:
\(\frac{77}{60} = 1\frac{17}{60}\)
So, the total sum is:
\(\text{Total Sum} = 14 + 1\frac{17}{60} = 15\frac{17}{60}\)
The sum is \(15\frac{17}{60}\). This means the sum is between the whole numbers 15 and 16. To make the result a whole number, we need to add a fraction to \(15\frac{17}{60}\) such that it becomes the next whole number, which is 16.
The fractional part of the sum is \(\frac{17}{60}\). To reach the next whole number (by completing the fraction to 1), we need to add a fraction that, when combined with \(\frac{17}{60}\), equals 1 (\(\frac{60}{60}\)).
The required smallest fraction is \(1 - \text{fractional part of the sum}\).
Required fraction \( = 1 - \frac{17}{60}\)
To subtract, we write 1 as \(\frac{60}{60}\):
Required fraction \( = \frac{60}{60} - \frac{17}{60} = \frac{60 - 17}{60} = \frac{43}{60}\)
Therefore, the smallest fraction that should be added to the sum of \(2\frac{1}{2}\), \(3\frac{1}{3}\), \(4\frac{1}{4}\), and \(5\frac{1}{5}\) to make the result a whole number is \(\frac{43}{60}\).
| Step | Description | Calculation |
|---|---|---|
| 1 | Sum of whole parts | \(2 + 3 + 4 + 5 = 14\) |
| 2 | Sum of fractional parts | \(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5}\) |
| 3 | Find common denominator (LCM of 2, 3, 4, 5) | 60 |
| 4 | Convert fractions and sum | \(\frac{30}{60} + \frac{20}{60} + \frac{15}{60} + \frac{12}{60} = \frac{77}{60}\) |
| 5 | Total sum | \(14 + \frac{77}{60} = 14 + 1\frac{17}{60} = 15\frac{17}{60}\) |
| 6 | Fraction needed to reach next whole number | \(1 - \frac{17}{60} = \frac{43}{60}\) |
The sum of the given mixed numbers is \(15\frac{17}{60}\). To make this a whole number, we need to add the difference between 1 and the fractional part \(\frac{17}{60}\), which is \(\frac{43}{60}\). Adding \(\frac{43}{60}\) to \(15\frac{17}{60}\) results in \(15 + \frac{17}{60} + \frac{43}{60} = 15 + \frac{60}{60} = 15 + 1 = 16\), which is a whole number.
| Term | Definition | Example |
|---|---|---|
| Mixed Number | A number consisting of a whole number and a proper fraction. | \(3\frac{1}{4}\) |
| Improper Fraction | A fraction where the numerator is greater than or equal to the denominator. | \(\frac{7}{4}\) |
| Proper Fraction | A fraction where the numerator is less than the denominator. | \(\frac{3}{4}\) |
| Whole Number | Any non-negative integer (0, 1, 2, 3,...). | 15, 16 |
| Least Common Multiple (LCM) | The smallest positive integer that is a multiple of two or more numbers. Essential for adding/subtracting fractions. | LCM of 2, 3, 4, 5 is 60. |
There are typically two ways to add mixed numbers:
In this specific problem, finding the fraction needed to reach a whole number requires focusing on the fractional part of the final sum, making Method 1 more direct for the calculation steps shown.
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Which of the following is correct?
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Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
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d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |
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