Let a, b and c be the fractions such that a < b < c. If c is divided by a, the result is 5/2, which exceeds b by 7/4, If \(a + b + c = 1\frac{{11}}{{12}},\) then (c – a) will be equal to:
1/2
Step 1 — Find b: Since \(c/a=5/2\) exceeds b by 7/4,
\[b=\dfrac{5}{2}-\dfrac{7}{4}=\dfrac{10-7}{4}=\dfrac{3}{4}\]
Step 2 — Find a: With \(c=\tfrac{5}{2}a\) and \(a+b+c=\tfrac{23}{12}\):
\[a+\dfrac{3}{4}+\dfrac{5}{2}a=\dfrac{23}{12}\implies \dfrac{7}{2}a=\dfrac{14}{12}=\dfrac{7}{6}\]
\[a=\dfrac{1}{3},\quad c=\dfrac{5}{2}\cdot\dfrac{1}{3}=\dfrac{5}{6}\]
Therefore \(c-a=\dfrac{5}{6}-\dfrac{1}{3}=\dfrac{3}{6}=\mathbf{\tfrac{1}{2}}\).
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is:
Three fractions x, y and z are such that x > y > z. When the smallest of them is divided by the greatest, the result is \({\frac{9}{16}}\) , which exceeds y by 0.0625. If x + y + z = \(2{\frac{3}{12}}\) , then what is the value of x + z?
The value of \(\frac{52-1170\div26+13\times2}{2+1\frac{1}{8}\ \rm of\ 2-1\frac{1}{4}}\) is:
The value of 25 ÷ 15 of 4 × [4 ÷ 5 × (9 - 7)] - (20 ÷ 5 of 9) is:
If \(\frac{1}{{x + \frac{1}{{y + \frac{2}{{z + \frac{1}{4}}}}}}} = \frac{{29}}{{79}}\) where x, y, and z are natural numbers, then the value of (2x + 3y - z) is:
The sum of three numbers is 2, the 1st number is 1/2 times the 2nd number andthe 3rd number is 1/4 times the 2nd number. The 2nd number is
Which of the following is correct?
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |
Among the fractions \(\frac{7}{12}\) , \(\frac{8}{15}\) , \(\frac{17}{24}\) and \(\frac{13}{18}\) , which is the smallest?