The second and fourth moment about mean for a distribution are 4 and 18 respectively. What is the value of Pearson's coefficient of skewness β z?
1.125
The question labels the coefficient as skewness but the only computable quantity from the given moments \(\mu_2\) and \(\mu_4\) is the Pearson kurtosis coefficient:
\[\beta_2 = \frac{\mu_4}{\mu_2^{2}} = \frac{18}{4^{2}} = \frac{18}{16} = \frac{9}{8} = 1.125\]
Hence the value is 1.125.
The first four moments of a distribution about the value 2 are 1, 2.5, 5.5 and 16. What is the 4th moment about zero?
Given below are moments about an arbitrary origin 5.
If μ'1 = -4, μ'2 = 22, μ'3 = -117 and μ'4 = 560, then μ3 is equal to:
The third order central moment of normal distribution is:
If μ'r and μr, respectively, denote rth order moments about origin and mean, then:
The standard deviation of a symmetrical distribution is 3. What must be the value of the fourth moment about the mean for the distribution to be mesokurtic?
The first four moments of a distribution about the origin are -1.5, 17, -30 and 108. The third moment about the mean is:
μ' (r) and μ' rrepresent the factorial moment of order r about the origin and r th moment about the origin of the distribution x i|f i, i = 1, 2, … n. The value of μ' 2equals to:
For a random variable x, the central moments ( \(\mu \)i ) of all order exist. The square of (2j + 1) th moment ( \(\mu^2_2{_j}{_+}{_1}\) ) is
The first four moments of a distribution about the value 2 are 1, 2.5, 5.5 and 16. What is the 4th moment about zero?
Given below are moments about an arbitrary origin 5.
If μ'1 = -4, μ'2 = 22, μ'3 = -117 and μ'4 = 560, then μ3 is equal to:
The third order central moment of normal distribution is:
If μ'r and μr, respectively, denote rth order moments about origin and mean, then:
The standard deviation of a symmetrical distribution is 3. What must be the value of the fourth moment about the mean for the distribution to be mesokurtic?