Given below are moments about an arbitrary origin 5.
If μ'1 = -4, μ'2 = 22, μ'3 = -117 and μ'4 = 560, then μ3 is equal to:
19
To convert central moments from moments about arbitrary origin, use the transformation formulas. For the third moment: μ3 = μ'3 - 3μ'1μ'2 + 2(μ'1)3
= -117 - 3(-4)(22) + 2(-4)3 = -117 + 264 - 128 = 19.
The first four moments of a distribution about the value 2 are 1, 2.5, 5.5 and 16. What is the 4th moment about zero?
The third order central moment of normal distribution is:
If μ'r and μr, respectively, denote rth order moments about origin and mean, then:
The standard deviation of a symmetrical distribution is 3. What must be the value of the fourth moment about the mean for the distribution to be mesokurtic?
The first four moments of a distribution about the origin are -1.5, 17, -30 and 108. The third moment about the mean is:
μ' (r) and μ' rrepresent the factorial moment of order r about the origin and r th moment about the origin of the distribution x i|f i, i = 1, 2, … n. The value of μ' 2equals to:
The second and fourth moment about mean for a distribution are 4 and 18 respectively. What is the value of Pearson's coefficient of skewness β z?
For a random variable x, the central moments ( \(\mu \)i ) of all order exist. The square of (2j + 1) th moment ( \(\mu^2_2{_j}{_+}{_1}\) ) is
The first four moments of a distribution about the value 2 are 1, 2.5, 5.5 and 16. What is the 4th moment about zero?
The third order central moment of normal distribution is:
If μ'r and μr, respectively, denote rth order moments about origin and mean, then:
The standard deviation of a symmetrical distribution is 3. What must be the value of the fourth moment about the mean for the distribution to be mesokurtic?
The first four moments of a distribution about the origin are -1.5, 17, -30 and 108. The third moment about the mean is: