The problem asks us to find the radius ($r$) of a circle given the arc length ($s$) and the central angle ($\theta$) it subtends. We are given:
The formula connecting arc length, radius, and central angle is $s = r\theta$, where $\theta$ must be in radians.
To use the formula, we convert the angle from degrees to radians:
$\theta_{\text{radians}} = \theta_{\text{degrees}} \times \frac{\pi}{180^{\circ}}$
$\theta = 60^{\circ} \times \frac{\pi}{180^{\circ}} = \frac{60\pi}{180} = \frac{\pi}{3}$ radians.
Now, substitute the known values into the arc length formula $s = r\theta$:
$35\text{ cm} = r \times \frac{\pi}{3}$
To solve for $r$, rearrange the equation:
$r = \frac{35\text{ cm}}{\frac{\pi}{3}}$
$r = 35 \times \frac{3}{\pi}\text{ cm}$
$r = \frac{105}{\pi}\text{ cm}$
The radius of the circle is $\frac{105}{\pi}\text{ cm}$. This corresponds to Option 1.
If 2x(x + y + z) = 250, 2y(x + y + z) = 100, 2z(x + y + z) = 100, then find the value of (3x + 6y + 15z).
If x + 2y = 27 and x - 2y = -1, find the value of y.
Solve: If 8x + 5y = 9 and 3x + 2y = 4, find the value of x.
A.-2
B.5
C.2
D.-5
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
1 + tan 15° cot 75° is equal to:
The value of cot (-315°) is :
θ = 135°; γ = 15°.
What is the value of 2 cos(θ) sin(γ)?
If tan(90 – θ) = \(\frac{2}{\sqrt3}\), then the value of \(2\sqrt3\) tan θ + 1 is: