(take $\pi =3.14$)
This solution details how to calculate the distance covered by the tip of a watch's minute hand over a specific period.
We are given the following information:
The minute hand completes a full circle ($360^\circ$) in $60$ minutes.
For calculations involving arc length, the angle must be in radians.
The distance the tip moves is the arc length (s) along the circle.
The formula for arc length is $s = r\theta$, where $r$ is the radius and $\theta$ is the angle in radians.
Substitute the given value of $\pi = 3.14$ into the simplified expression:
Therefore, the tip of the minute hand moves $6.28\text{ cm}$ in $40\text{ minutes}$.
If x + 2y = 27 and x - 2y = -1, find the value of y.
If 2x(x + y + z) = 250, 2y(x + y + z) = 100, 2z(x + y + z) = 100, then find the value of (3x + 6y + 15z).
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
1 + tan 15° cot 75° is equal to:
If tan θ = 1/√5, find the value of cosec2θ – sec2θ.
If cos A = \(\frac{63}{65}\), then find the value of tan A + cot A (up to two places of decimal).
If A = 60° and B = 30°, find the value of \(\frac{(\tan A-\tan B)}{(1+\tan A \tan B)}\).