(take $\pi =3.14$)
This solution details how to calculate the distance covered by the tip of a watch's minute hand over a specific period.
We are given the following information:
The minute hand completes a full circle ($360^\circ$) in $60$ minutes.
For calculations involving arc length, the angle must be in radians.
The distance the tip moves is the arc length (s) along the circle.
The formula for arc length is $s = r\theta$, where $r$ is the radius and $\theta$ is the angle in radians.
Substitute the given value of $\pi = 3.14$ into the simplified expression:
Therefore, the tip of the minute hand moves $6.28\text{ cm}$ in $40\text{ minutes}$.
Which of the following values of A and B satisfies, sin(A + B) = sin A + sin B, where
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
The value of 4cos\(\left( {\frac{\pi }{6}\, - \,\alpha } \right)\) sin\(\left( {\frac{\pi }{3}\, - \,\alpha } \right)\) is equal to:
1 + tan 15° cot 75° is equal to:
If tan θ = 1/√5, find the value of cosec2θ – sec2θ.