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Question

Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cm.

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper PDF (31-Jan-2021) (Shift 1)
The correct answer is
$12^{\circ} \text{ } 36'$

Finding Central Angle from Arc Length

We are asked to find the degree measure of the angle subtended at the center of a circle given the circle's radius and the length of the arc.

Given:

  • Radius of the circle, $r = 100$ cm
  • Arc length, $L = 22$ cm

Calculating Angle in Radians

The formula relating arc length ($L$), radius ($r$), and the central angle in radians ($\theta_{rad}$) is:

$ L = r \times \theta_{rad} $

Rearranging the formula to solve for $\theta_{rad}$:

$ \theta_{rad} = \frac{L}{r} $

Substituting the given values:

$ \theta_{rad} = \frac{22 \text{ cm}}{100 \text{ cm}} = 0.22 \text{ radians} $

Converting Radians to Degrees

To convert an angle from radians to degrees, we use the conversion factor $\frac{180^{\circ}}{\pi}$.

$ \theta_{deg} = \theta_{rad} \times \frac{180^{\circ}}{\pi} $

We can approximate $\pi$ as $\frac{22}{7}$.

$ \theta_{deg} = 0.22 \times \frac{180^{\circ}}{22/7} $

$ \theta_{deg} = \frac{22}{100} \times \frac{180 \times 7}{22} $

Cancel out the 22s:

$ \theta_{deg} = \frac{1}{100} \times 180 \times 7 $

$ \theta_{deg} = \frac{180 \times 7}{100} = \frac{18 \times 7}{10} = \frac{126}{10} $

$ \theta_{deg} = 12.6^{\circ} $

Expressing Angle in Degrees and Minutes

The angle is $12.6$ degrees. The decimal part ($0.6$) needs to be converted into minutes.

There are 60 minutes in a degree ($1^{\circ} = 60'$).

Minutes $= 0.6 \times 60'$

Minutes $= 36'$

Therefore, the angle in degrees and minutes is $12^{\circ} 36'$.

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Similar Questions

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  2. The radius of the circle in which a central angle of $60^{\circ}$ intercepts an arc of length $35\text{ cm}$ is:
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Important Questions from Circular Measure of Angles

  1. If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.

  2. 1 + tan 15° cot 75° is equal to:

  3. The value of cot (-315°) is :

  4. θ = 135°; γ = 15°.

    What is the value of 2 cos(θ) sin(γ)?

  5. If tan(90 – θ) = \(\frac{2}{\sqrt3}\), then the value of \(2\sqrt3\) tan θ + 1 is:

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