We are asked to find the degree measure of the angle subtended at the center of a circle given the circle's radius and the length of the arc.
Given:
The formula relating arc length ($L$), radius ($r$), and the central angle in radians ($\theta_{rad}$) is:
$ L = r \times \theta_{rad} $
Rearranging the formula to solve for $\theta_{rad}$:
$ \theta_{rad} = \frac{L}{r} $
Substituting the given values:
$ \theta_{rad} = \frac{22 \text{ cm}}{100 \text{ cm}} = 0.22 \text{ radians} $
To convert an angle from radians to degrees, we use the conversion factor $\frac{180^{\circ}}{\pi}$.
$ \theta_{deg} = \theta_{rad} \times \frac{180^{\circ}}{\pi} $
We can approximate $\pi$ as $\frac{22}{7}$.
$ \theta_{deg} = 0.22 \times \frac{180^{\circ}}{22/7} $
$ \theta_{deg} = \frac{22}{100} \times \frac{180 \times 7}{22} $
Cancel out the 22s:
$ \theta_{deg} = \frac{1}{100} \times 180 \times 7 $
$ \theta_{deg} = \frac{180 \times 7}{100} = \frac{18 \times 7}{10} = \frac{126}{10} $
$ \theta_{deg} = 12.6^{\circ} $
The angle is $12.6$ degrees. The decimal part ($0.6$) needs to be converted into minutes.
There are 60 minutes in a degree ($1^{\circ} = 60'$).
Minutes $= 0.6 \times 60'$
Minutes $= 36'$
Therefore, the angle in degrees and minutes is $12^{\circ} 36'$.
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