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Question

The number of triangles formed by diagonals from one vertex of an octagon is:

This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is
6

Octagon Triangles: Calculating Diagonals from a Vertex

To find the number of triangles formed by drawing diagonals from a single vertex of a polygon, we can use a simple geometric principle.

Consider drawing diagonals from one vertex of an $n$-sided polygon (an $n$-gon). A diagonal connects the chosen vertex to any other vertex except its two adjacent ones.

  • Choosing diagonals from one vertex creates triangles by connecting that vertex to non-adjacent vertices.
  • Each diagonal, along with two sides of the polygon originating from that vertex, forms a triangle.
  • An $n$-sided polygon has $n$ vertices. From one vertex, you can draw $n-3$ diagonals (to all vertices except itself and its two neighbours).
  • These $n-3$ diagonals divide the polygon into $n-2$ distinct triangles.

Applying the Triangle Formula

The formula to calculate the number of triangles formed by diagonals from one vertex of an $n$-sided polygon is:

Number of Triangles = $n - 2$

Calculation for an Octagon

An octagon is a polygon with 8 sides. Therefore, for an octagon, $n = 8$.

Using the formula:

Number of Triangles = $8 - 2 = 6$

Thus, 6 triangles are formed by drawing diagonals from one vertex of an octagon.

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