To find the number of triangles formed by drawing diagonals from a single vertex of a polygon, we can use a simple geometric principle.
Consider drawing diagonals from one vertex of an $n$-sided polygon (an $n$-gon). A diagonal connects the chosen vertex to any other vertex except its two adjacent ones.
The formula to calculate the number of triangles formed by diagonals from one vertex of an $n$-sided polygon is:
Number of Triangles = $n - 2$
An octagon is a polygon with 8 sides. Therefore, for an octagon, $n = 8$.
Using the formula:
Number of Triangles = $8 - 2 = 6$
Thus, 6 triangles are formed by drawing diagonals from one vertex of an octagon.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.