A man spends in 8 months as much as he earns in 6 months. He saves Rs. 6000 in a year. His average monthly income is:
Rs. 2000
Let the man's monthly income be Rs. \(x\).
In 6 months, he earns \(6x\).
In 8 months, he spends \(8x\).
Given that the amount he spends in 8 months is equal to the amount he earns in 6 months:
\(8y = 6x\)
where \(y\) is his monthly expenditure.
His annual saving is Rs. 6000. His annual income is \(12x\), and his annual expenditure is \(12y\).
Therefore, his annual saving can be expressed as:
\(12x - 12y = 6000\)
Dividing by 12:
\(x - y = 500\)
We know that \(8y = 6x\), so \(4y = 3x\), which means \(y = \frac{3}{4}x\).
Substitute this into \(x - y = 500\):
\(x - \frac{3}{4}x = 500\)
\(\frac{1}{4}x = 500\)
\(x = 2000\)
Therefore, his average monthly income is Rs. 2000.
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