Direction: Read the following information and answer the four items that follow: Let the distribution of the number of scooters of companies X and Y sold by 5 showrooms (A, B, C, D and E) in a certain year be denoted S1 and the distribution of the number of scooters of only company X sold by the five showrooms in the same year be denoted by S2. Showroom A B C D E Total number of scooters sold S1 (in%) 19 21 15 33 12 6400 S2 (in%) 24 18 20 30 8 3000
The number of scooters of both the companies sold by showroom B is what per cent more than the number of scooters of company X sold by showroom A?
The question asks us to compare the sales of scooters from different showrooms and companies based on the provided distribution data. We have two distributions:
We need to find out how much more (in percentage) the number of scooters of both companies sold by showroom B is compared to the number of scooters of company X sold by showroom A.
First, let's calculate the exact number of scooters sold by showroom B (both companies) using S1 and the number of scooters sold by showroom A (only company X) using S2.
| Showroom | S1 (Total Scooters) Percentage | S2 (Company X Scooters) Percentage |
|---|---|---|
| A | 19% | 24% |
| B | 21% | 18% |
| C | 15% | 20% |
| D | 33% | 30% |
| E | 12% | 8% |
| Total | 100% (6400) | 100% (3000) |
From distribution S1, showroom B accounts for 21% of the total 6400 scooters.
Number of scooters (X + Y) by showroom B = \(21\% \text{ of } 6400\)
Number of scooters (X + Y) by showroom B = \(\frac{21}{100} \times 6400\)
Number of scooters (X + Y) by showroom B = \(21 \times 64\)
Number of scooters (X + Y) by showroom B = \(1344\)
From distribution S2, showroom A accounts for 24% of the total 3000 scooters of company X.
Number of scooters (X) by showroom A = \(24\% \text{ of } 3000\)
Number of scooters (X) by showroom A = \(\frac{24}{100} \times 3000\)
Number of scooters (X) by showroom A = \(24 \times 30\)
Number of scooters (X) by showroom A = \(720\)
Now we need to find out what percentage the number of scooters sold by showroom B (1344) is more than the number of scooters sold by showroom A (720).
First, calculate the difference in the number of scooters:
Difference = (Scooters by showroom B) - (Scooters by showroom A)
Difference = \(1344 - 720 = 624\)
Next, calculate the percentage increase. The percentage is calculated with respect to the number of scooters sold by showroom A (720).
Percentage More = \(\frac{\text{Difference}}{\text{Number of Scooters by Showroom A}} \times 100\%\)
Percentage More = \(\frac{624}{720} \times 100\%\)
Let's simplify the fraction:
\(\frac{624}{720} = \frac{624 \div 8}{720 \div 8} = \frac{78}{90}\)
\(\frac{78}{90} = \frac{78 \div 6}{90 \div 6} = \frac{13}{15}\)
Now substitute the simplified fraction back into the percentage calculation:
Percentage More = \(\frac{13}{15} \times 100\%\)
Percentage More = \(\frac{1300}{15}\%\)
Percentage More = \(\frac{1300 \div 5}{15 \div 5}\% = \frac{260}{3}\%\)
To express this as a mixed number, divide 260 by 3:
\(260 \div 3\)
\(260 = 3 \times 86 + 2\)
So, \(\frac{260}{3} = 86 \frac{2}{3}\)
The number of scooters of both companies sold by showroom B is \(86\frac{2}{3}\%\) more than the number of scooters of company X sold by showroom A.
| Metric | Value | Calculation Source |
|---|---|---|
| Total Scooters (S1) | 6400 | Given data |
| Total Company X Scooters (S2) | 3000 | Given data |
| % S1 for Showroom B | 21% | Given data |
| % S2 for Showroom A | 24% | Given data |
| Scooters (X+Y) Showroom B | 1344 | 21% of 6400 |
| Scooters (X) Showroom A | 720 | 24% of 3000 |
| Difference | 624 | 1344 - 720 |
| Percentage More | \(86\frac{2}{3}\%\) | \(\frac{624}{720} \times 100\%\) |
Understanding percentage change is crucial for data interpretation problems like this. Percentage change tells us the relative change between an old value and a new value.
These types of questions combine data analysis from tables/distributions with basic percentage calculations.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?