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Question

Direction: Read the following information and answer the four items that follow:

Let the distribution of the number of scooters of companies X and Y sold by 5 showrooms (A, B, C, D and E) in a certain year be denoted S1 and the distribution of the number of scooters of only company X sold by the five showrooms in the same year be denoted by S2.

Showroom

A

B

C

D

E

Total number of

scooters sold

S1 (in%)

19

21

15

33

12

6400

S2 (in%)

24

18

20

30

8

3000

The number of scooters of both the companies sold by showroom B is what per cent more than the number of scooters of company X sold by showroom A?

This question was previously asked in
CDS I 2019 Elementary Mathematics Previous Year Paper (03-Feb-2019)
The correct answer is \(86\frac{2}{3}\)

The question asks us to compare the sales of scooters from different showrooms and companies based on the provided distribution data. We have two distributions:

  • S1: Distribution of the total number of scooters (Company X + Company Y) sold by 5 showrooms (A, B, C, D, E). The total number of scooters in S1 is 6400.
  • S2: Distribution of the number of scooters of only Company X sold by the same 5 showrooms. The total number of scooters in S2 is 3000.

We need to find out how much more (in percentage) the number of scooters of both companies sold by showroom B is compared to the number of scooters of company X sold by showroom A.

Calculating Scooter Sales per Showroom

First, let's calculate the exact number of scooters sold by showroom B (both companies) using S1 and the number of scooters sold by showroom A (only company X) using S2.

Showroom S1 (Total Scooters) Percentage S2 (Company X Scooters) Percentage
A 19% 24%
B 21% 18%
C 15% 20%
D 33% 30%
E 12% 8%
Total 100% (6400) 100% (3000)

Number of Scooters (X + Y) Sold by Showroom B

From distribution S1, showroom B accounts for 21% of the total 6400 scooters.

Number of scooters (X + Y) by showroom B = \(21\% \text{ of } 6400\)

Number of scooters (X + Y) by showroom B = \(\frac{21}{100} \times 6400\)

Number of scooters (X + Y) by showroom B = \(21 \times 64\)

Number of scooters (X + Y) by showroom B = \(1344\)

Number of Scooters (only X) Sold by Showroom A

From distribution S2, showroom A accounts for 24% of the total 3000 scooters of company X.

Number of scooters (X) by showroom A = \(24\% \text{ of } 3000\)

Number of scooters (X) by showroom A = \(\frac{24}{100} \times 3000\)

Number of scooters (X) by showroom A = \(24 \times 30\)

Number of scooters (X) by showroom A = \(720\)

Calculating the Percentage More

Now we need to find out what percentage the number of scooters sold by showroom B (1344) is more than the number of scooters sold by showroom A (720).

First, calculate the difference in the number of scooters:

Difference = (Scooters by showroom B) - (Scooters by showroom A)

Difference = \(1344 - 720 = 624\)

Next, calculate the percentage increase. The percentage is calculated with respect to the number of scooters sold by showroom A (720).

Percentage More = \(\frac{\text{Difference}}{\text{Number of Scooters by Showroom A}} \times 100\%\)

Percentage More = \(\frac{624}{720} \times 100\%\)

Let's simplify the fraction:

\(\frac{624}{720} = \frac{624 \div 8}{720 \div 8} = \frac{78}{90}\)

\(\frac{78}{90} = \frac{78 \div 6}{90 \div 6} = \frac{13}{15}\)

Now substitute the simplified fraction back into the percentage calculation:

Percentage More = \(\frac{13}{15} \times 100\%\)

Percentage More = \(\frac{1300}{15}\%\)

Percentage More = \(\frac{1300 \div 5}{15 \div 5}\% = \frac{260}{3}\%\)

To express this as a mixed number, divide 260 by 3:

\(260 \div 3\)

\(260 = 3 \times 86 + 2\)

So, \(\frac{260}{3} = 86 \frac{2}{3}\)

The number of scooters of both companies sold by showroom B is \(86\frac{2}{3}\%\) more than the number of scooters of company X sold by showroom A.

Revision Table: Scooter Sales Analysis

Metric Value Calculation Source
Total Scooters (S1) 6400 Given data
Total Company X Scooters (S2) 3000 Given data
% S1 for Showroom B 21% Given data
% S2 for Showroom A 24% Given data
Scooters (X+Y) Showroom B 1344 21% of 6400
Scooters (X) Showroom A 720 24% of 3000
Difference 624 1344 - 720
Percentage More \(86\frac{2}{3}\%\) \(\frac{624}{720} \times 100\%\)

Additional Information on Percentage Change

Understanding percentage change is crucial for data interpretation problems like this. Percentage change tells us the relative change between an old value and a new value.

  • Percentage Increase: Used when the new value is greater than the old value. Formula: \(\frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \times 100\%\). This is equivalent to \(\frac{\text{Difference}}{\text{Original Value}} \times 100\%\) when calculating how much 'more' something is compared to the original.
  • Percentage Decrease: Used when the new value is less than the old value. Formula: \(\frac{\text{Old Value} - \text{New Value}}{\text{Old Value}} \times 100\%\).
  • It is very important to correctly identify the 'Old Value' or 'Original Value' which serves as the base for the percentage calculation. In this question, we are asked "what per cent more than the number of scooters of company X sold by showroom A", so the number of scooters sold by showroom A (720) is the base (the 'Original Value').

These types of questions combine data analysis from tables/distributions with basic percentage calculations.

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Important Questions from Tabulation

  1. Table shows income (in Rs.) received by 4 employees of a company during the month of December 2020 and all their income sources.

    Source

    Amit

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    Salary

    35000

    38000

    29000

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    Arrears

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    1000

    1100

    1000

    1240

    Overtime

    1800

    1950

    1400

    1500


    By what percent are the Arrears of Amit and Suresh taken together less than the Arrears of Nitin and Varun taken together?
  2. The table given below shows the GDP of two countries in different five years.

    Country
    YearsAB
    Y1175285
    Y2200300
    Y3150125
    Y47585
    Y55095

    K1 = The value of average GDP of country A in all the 5 years.

    K2 = The value of average GDP of country B in all the 5 years.

    What is the value of (K1 + K2)?

  3. Study the Table Properly and answer by interpreting the data

    The table shows the percentage population of five districts in a state below poverty line and the proportion of males and females.

    DistrictPercentage of population
    below poverty level
    Proportion of Male and Female 
    Below poverty line (M:F)Above poverty Line (M:F)
    D1152 : 33 : 2
    D2183 : 47 : 5
    D3202 : 53 : 4
    D4255 : 24 : 3
    D5123 : 72 : 7

    If the total population in the district D3 is 40,000, then what is the population of below poverty line in the district D3, ?

  4. The table given below shows the marks obtained by 4 students in 5 subjects. The maximum marks of each subject is 100.

    Subjects

    Students

    P1

    P2

    P3

    P4

    S1

    89

    100

    92

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    S2

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    52

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    S3

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    55

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    65

    S4

    76

    85

    76

    58

    S5

    85

    70

    66

    62

    What is the total percent marks of P4?

  5. The data given below shows the number of people who have saved a certain amount of money.

    Savings

    (in Rs.)

    Number of people

    5

    1

    15

    3

    20

    4

    25

    2

    30

    1

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