Direction: Read the following information and answer the four items that follow: Let the distribution of the number of scooters of companies X and Y sold by 5 showrooms (A, B, C, D and E) in a certain year be denoted S1 and the distribution of the number of scooters of only company X sold by the five showrooms in the same year be denoted by S2. Showroom A B C D E Total number of scooters sold S1 (in%) 19 21 15 33 12 6400 S2 (in%) 24 18 20 30 8 3000
The number of scooters of both the companies sold by showroom B is what per cent more than the number of scooters of company X sold by showroom A?
The question asks us to compare the sales of scooters from different showrooms and companies based on the provided distribution data. We have two distributions:
We need to find out how much more (in percentage) the number of scooters of both companies sold by showroom B is compared to the number of scooters of company X sold by showroom A.
First, let's calculate the exact number of scooters sold by showroom B (both companies) using S1 and the number of scooters sold by showroom A (only company X) using S2.
| Showroom | S1 (Total Scooters) Percentage | S2 (Company X Scooters) Percentage |
|---|---|---|
| A | 19% | 24% |
| B | 21% | 18% |
| C | 15% | 20% |
| D | 33% | 30% |
| E | 12% | 8% |
| Total | 100% (6400) | 100% (3000) |
From distribution S1, showroom B accounts for 21% of the total 6400 scooters.
Number of scooters (X + Y) by showroom B = \(21\% \text{ of } 6400\)
Number of scooters (X + Y) by showroom B = \(\frac{21}{100} \times 6400\)
Number of scooters (X + Y) by showroom B = \(21 \times 64\)
Number of scooters (X + Y) by showroom B = \(1344\)
From distribution S2, showroom A accounts for 24% of the total 3000 scooters of company X.
Number of scooters (X) by showroom A = \(24\% \text{ of } 3000\)
Number of scooters (X) by showroom A = \(\frac{24}{100} \times 3000\)
Number of scooters (X) by showroom A = \(24 \times 30\)
Number of scooters (X) by showroom A = \(720\)
Now we need to find out what percentage the number of scooters sold by showroom B (1344) is more than the number of scooters sold by showroom A (720).
First, calculate the difference in the number of scooters:
Difference = (Scooters by showroom B) - (Scooters by showroom A)
Difference = \(1344 - 720 = 624\)
Next, calculate the percentage increase. The percentage is calculated with respect to the number of scooters sold by showroom A (720).
Percentage More = \(\frac{\text{Difference}}{\text{Number of Scooters by Showroom A}} \times 100\%\)
Percentage More = \(\frac{624}{720} \times 100\%\)
Let's simplify the fraction:
\(\frac{624}{720} = \frac{624 \div 8}{720 \div 8} = \frac{78}{90}\)
\(\frac{78}{90} = \frac{78 \div 6}{90 \div 6} = \frac{13}{15}\)
Now substitute the simplified fraction back into the percentage calculation:
Percentage More = \(\frac{13}{15} \times 100\%\)
Percentage More = \(\frac{1300}{15}\%\)
Percentage More = \(\frac{1300 \div 5}{15 \div 5}\% = \frac{260}{3}\%\)
To express this as a mixed number, divide 260 by 3:
\(260 \div 3\)
\(260 = 3 \times 86 + 2\)
So, \(\frac{260}{3} = 86 \frac{2}{3}\)
The number of scooters of both companies sold by showroom B is \(86\frac{2}{3}\%\) more than the number of scooters of company X sold by showroom A.
| Metric | Value | Calculation Source |
|---|---|---|
| Total Scooters (S1) | 6400 | Given data |
| Total Company X Scooters (S2) | 3000 | Given data |
| % S1 for Showroom B | 21% | Given data |
| % S2 for Showroom A | 24% | Given data |
| Scooters (X+Y) Showroom B | 1344 | 21% of 6400 |
| Scooters (X) Showroom A | 720 | 24% of 3000 |
| Difference | 624 | 1344 - 720 |
| Percentage More | \(86\frac{2}{3}\%\) | \(\frac{624}{720} \times 100\%\) |
Understanding percentage change is crucial for data interpretation problems like this. Percentage change tells us the relative change between an old value and a new value.
These types of questions combine data analysis from tables/distributions with basic percentage calculations.
Consider the following data with regard to production of cars (In lakhs):
Year 2015 | Year 2016 | |
Country A | 35 | 38 |
Country B | 45 | 47 |
Country C | 88 | 93 |
Country D | 75 | 79 |
Country E | 58 | 60.9 |
The following table shows the marks of 90 students in a test of 80 marks:
Marks | Number of Students |
1 – 10 | 5 |
11 – 20 | 8 |
21 – 30 | 10 |
31 – 40 | 13 |
41 – 50 | 18 |
51 – 60 | 17 |
61 – 70 | 12 |
71 – 80 | 7 |
What is the total population of the city (in lakhs)?
If the ratio of taxpayers to other persons in the same age group below 30 years is 1 : 2, then what is the number of taxpayers (in lakhs) in that age group?
How many times the increase in expenditure in a year exceeded by more than 15% as compared to previous year?
In which year, the percentage increase in expenditure is maximum as compared to its previous year?
In which one of the following pairs of years, the difference in total number of tablets produced between them is minimum?
The ratio of percentage drop in total production in 2004 compared to 2001 to that in 2000 compared to 2001, is
In which year, the production of Type 1 is more than the sum of the production of Type 3 and Type 4?
Jails with highest and smallest percentage of trained convicts are respectively:
What is the ratio of total number of patients recovered from covid-19 in April to total number of patients recovered from covid-19 in March?
In which state, the number of patients who recovered from covid-19 steadily decreasing?
What is the average number of patients who recovered from Covid-19 in Madhya Pradesh in four months?
Find the difference between the total number of patients recovered from Covid-19 in all months in Punjab and the total number of patients recovered from Covid-19 in all months in Rajasthan.
In February 2021 the number of patients recovered from Covid-19 in Punjab is how much approximant percent more/less than the number of patients recovered from Covid-19 Uttar Pradesh in the same month?