The monthly expenditure of a person is Rs. 6,000. The distribution of expenditure on various items is as follows: Item of expenditure Amount (in Rs.) 1. Food 2,000 2. Clothing 660 3. Fuel and rent 1,200 4. Education 480 5. Miscellaneous 1,660
1.2 cm and 4.15 cm
The problem provides the monthly expenditure of a person, which totals Rs. 6,000. This expenditure is distributed across different items like Food, Clothing, Fuel and rent, Education, and Miscellaneous. We are given the amount spent on each item.
The data is to be represented using a percentage bar diagram with a total height of 15 cm. In a percentage bar diagram, the total height of the bar represents 100% of the total expenditure, and the length of each segment within the bar corresponds to the percentage share of the respective expenditure item.
The given distribution is as follows:
| Item of expenditure | Amount (in Rs.) |
| 1. Food | 2,000 |
| 2. Clothing | 660 |
| 3. Fuel and rent | 1,200 |
| 4. Education | 480 |
| 5. Miscellaneous | 1,660 |
First, let's verify the total expenditure from the given amounts:
Total Expenditure \(= 2000 + 660 + 1200 + 480 + 1660 = 6000\) Rs.
This matches the given total monthly expenditure.
To determine the length of each segment in the percentage bar diagram, we need to calculate the percentage of expenditure for each item relative to the total expenditure of Rs. 6,000.
The formula for percentage is: \(\text{Percentage} = \left( \frac{\text{Amount spent on item}}{\text{Total Expenditure}} \right) \times 100\)%
Let's check the sum of percentages: \(33.33\% + 11\% + 20\% + 8\% + 27.67\% = 100\%\) (approximately, due to rounding for Food and Miscellaneous, but the exact fractions sum to 1). Using fractions or exact decimals for calculation is better for precision.
The total height of the percentage bar diagram is 15 cm, representing 100% of the expenditure.
To find the length of the segment for a specific item, we multiply the total height by the percentage share of that item (expressed as a decimal or fraction).
Length of segment = (Percentage share / 100) \(\times\) Total height of bar
Education percentage is 8% or 0.08.
Length for Education \(= 0.08 \times 15 \text{ cm} = 1.20 \text{ cm}\)
Miscellaneous percentage is \(\frac{1660}{6000} = \frac{166}{600}\). Expressing this as a decimal: \(\frac{166}{600} \approx 0.27666...\)
Length for Miscellaneous \(= \frac{1660}{6000} \times 15 \text{ cm} = \frac{166}{600} \times 15 \text{ cm} = \frac{166 \times 15}{600} \text{ cm}\)
Simplify the fraction: \(\frac{166 \times 15}{600} = \frac{166 \times 1}{40} = \frac{83 \times 1}{20} = \frac{83}{20} \text{ cm}\)
Converting the fraction to a decimal: \(\frac{83}{20} = 4.15 \text{ cm}\)
So, the length of the segment for Education is 1.2 cm, and the length of the segment for Miscellaneous is 4.15 cm.
These values correspond to the lengths of the two segments requested in the question, corresponding to education and miscellaneous respectively.
| Item | Amount (Rs.) | Percentage Share (%) | Segment Length (cm) [Height = 15 cm] |
| Food | 2000 | \(\frac{2000}{6000} \times 100 = 33.33\) | \(0.3333 \times 15 \approx 5.00\) |
| Clothing | 660 | \(\frac{660}{6000} \times 100 = 11\) | \(0.11 \times 15 = 1.65\) |
| Fuel and rent | 1200 | \(\frac{1200}{6000} \times 100 = 20\) | \(0.20 \times 15 = 3.00\) |
| Education | 480 | \(\frac{480}{6000} \times 100 = 8\) | \(0.08 \times 15 = 1.20\) |
| Miscellaneous | 1660 | \(\frac{1660}{6000} \times 100 = 27.67\) | \(0.2767 \times 15 \approx 4.15\) |
| Total | 6000 | 100 | \(5.00 + 1.65 + 3.00 + 1.20 + 4.15 = 15.00\) |
The calculated segment lengths for Education (1.2 cm) and Miscellaneous (4.15 cm) match one of the provided options.
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