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Question

The majority charge carriers in n-type semiconductors are

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is

Electrons

Understanding Charge Carriers in Semiconductors

Semiconductors are materials like silicon (Si) or germanium (Ge) that have electrical conductivity between that of a conductor (like copper) and an insulator (like glass). Their conductivity can be significantly altered by adding small amounts of impurities, a process called doping.

There are two main types of semiconductors based on doping:

  • Intrinsic Semiconductors: Pure semiconductors with no impurities.
  • Extrinsic Semiconductors: Doped semiconductors. These are further divided into p-type and n-type.

What is an n-type Semiconductor?

An n-type semiconductor is created by doping an intrinsic semiconductor (like silicon) with pentavalent impurities. Pentavalent elements are those with five valence electrons, such as Phosphorus (P), Arsenic (As), or Antimony (Sb).

When a pentavalent atom replaces a silicon atom (which has four valence electrons) in the crystal lattice, four of its valence electrons form covalent bonds with the surrounding silicon atoms. The fifth valence electron is not needed for bonding and is relatively loosely bound to the impurity atom. This extra electron requires very little energy to break free and become a mobile charge carrier in the conduction band.

These impurity atoms are called donor atoms because they donate a free electron to the semiconductor material.

Majority and Minority Charge Carriers in n-type Semiconductors

In an intrinsic semiconductor, the number of free electrons in the conduction band is equal to the number of holes in the valence band. However, in an n-type semiconductor:

  • The doping process introduces a large number of extra electrons from the donor atoms.
  • These extra electrons add to the electrons already present due to thermal generation (breaking of covalent bonds in the base semiconductor).
  • This significantly increases the total number of free electrons.
  • The number of holes remains relatively small, primarily generated by thermal energy breaking the original covalent bonds of the base semiconductor atoms.

Therefore, in n-type semiconductors, the concentration of free electrons is much greater than the concentration of holes.

  • Majority Charge Carriers: Electrons
  • Minority Charge Carriers: Holes

The term 'n-type' comes from 'negative type', referring to the prevalence of negative charge carriers (electrons).

Charge Carriers in n-type Semiconductors
Carrier Type Source Relative Concentration
Electrons Donor impurities + Thermal generation Majority (High)
Holes Thermal generation Minority (Low)

Why Other Options are Incorrect

Let's briefly look at why the other options are not the majority charge carriers in n-type semiconductors:

  • Holes: As explained above, holes are the minority charge carriers in n-type semiconductors. They are the majority carriers in p-type semiconductors.
  • Neutrons: Neutrons are neutral particles found in the nucleus of atoms. They do not carry an electric charge and therefore cannot act as charge carriers in the context of electrical conduction in semiconductors.
  • Protons: Protons are positively charged particles found in the nucleus of atoms. While they carry charge, they are bound within the nucleus and are not mobile charge carriers responsible for current flow in typical semiconductor operation. Current flow in semiconductors involves the movement of free electrons and holes.

Summary of n-type Charge Carriers

In conclusion, adding pentavalent impurities to a semiconductor creates an excess of free electrons. These electrons are readily available to move through the material and conduct current. Hence, electrons are the majority charge carriers in n-type semiconductors.

Revision Table: Semiconductor Types & Carriers

Semiconductor Type Doping Impurity Type Majority Carrier Minority Carrier
Intrinsic None (Pure) Electrons & Holes (Equal) None
n-type Pentavalent (Donor) Electrons Holes
p-type Trivalent (Acceptor) Holes Electrons

Additional Information on Semiconductor Doping

Doping is a crucial process for controlling the conductivity of semiconductors and enabling their use in electronic devices like diodes and transistors. The level of doping determines the concentration of majority carriers and thus the conductivity of the extrinsic semiconductor.

The electrical conductivity (\(\sigma\)) of an extrinsic semiconductor can be approximated by the contribution of the majority carriers. For n-type semiconductors, this is primarily due to electrons:

\(\sigma_n \approx n \cdot q \cdot \mu_n\)

Where:

  • \(n\) is the concentration of electrons
  • \(q\) is the elementary charge (magnitude of charge on an electron)
  • \(\mu_n\) is the electron mobility

The concentration of majority carriers (\(n\) in n-type) is largely determined by the concentration of the donor impurity atoms, assuming all donor atoms are ionized at typical operating temperatures.

Understanding the concept of majority and minority carriers is fundamental to understanding the operation of semiconductor devices and their applications in electronics.

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Important Questions from Carriers in Semiconductors

  1. In a pure silicon, what is the time for an electron to drift $1\mu m$ in an electric field of 100 V/cm? 

    Assume electron mobility of $1350 \text{ cm}^2/V-s$

  2. A. An impurity scattering cause decrease in mobility with decrease in temperature. 

    B. A slow moving carrier is likely to scatter more strongly than carrier with great momentum 

    C. Drift velocity of an electron increases with decrease in mobility 

    D. Drift velocity of an electron decrease with decrease in mobility 

    E. At critical electric field ($=10^5V/cm$) drift velocity tends to saturate. 

    Choose the correct answer from the options given below:

  3. An n-type GaAs Gunn diode has the following parameters drift velocity (Vd) = $10^7$ cm/s, Doping concentration = $2 \times 10^{14}$ cm$^{-3}$, and electric field = 3200 V/cm. Choose the correct option:
    A. Current density = 320 A/cm²
    B. Electron mobility = 3100 cm²/v-s
    C. Current density = 120 A/cm²
    D. Electron mobility = 1450 cm²/v-s
    E. Electron mobility = 1500 cm²/v-s
    Choose the correct answer from the options given below:
     

  4. Consider the following statements :

    If an electric field is applied to an n-type semiconductor bar, the electrons and holes move in opposite directions due to their opposite charges. The net current is

    1. due to both electrons and holes with electrons as majority carriers.
    2. the sum of electron and hole currents.
    3. the difference between electron and hole current.

    Which of these statements is/are correct ?

  5. Consider the following :

    1. In semiconductors, the mobility of electrons is more than that of holes.
    2. In semiconductors, the resistivity increases with the increase in temperature.
    3. Metal has positive TCR.
    4. In metals, thermal conductivity is inversely proportional to electronic conductivity at a particular temperature.

    Which of the following statements are correct ?

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