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Question

The velocity with which electrons are emitted in the photoemission process

The correct answer is

is a function of the wavelength of the incident light

Photoemission: Understanding Electron Velocity

The process of photoemission, also known as the photoelectric effect, involves the emission of electrons from a material when light shines on its surface. This phenomenon is crucial in understanding the quantum nature of light and matter interactions.

Electron Velocity and Wavelength of Incident Light

The velocity with which electrons are emitted in the photoemission process is determined by the energy of the incident photons and the work function of the material. According to Einstein's photoelectric equation, the maximum kinetic energy (KEmax) of the emitted photoelectrons is given by:

$$\text{KE}_{\text{max}} = h\nu - \phi$$

Where:

  • $$h$$ is Planck's constant.
  • $$\nu$$ is the frequency of the incident light.
  • $$\phi$$ (phi) is the work function of the metal, which is the minimum energy required to liberate an electron from the surface.

We know that the frequency $$\nu$$ of light is related to its wavelength $$\lambda$$ and the speed of light $$c$$ by the equation $$\nu = c/\lambda$$. Substituting this into the photoelectric equation, we get:

$$\text{KE}_{\text{max}} = \frac{hc}{\lambda} - \phi$$

The kinetic energy of an emitted electron is also given by $$\frac{1}{2}mv^2$$, where $$m$$ is the mass of the electron and $$v$$ is its velocity. Therefore:

$$\frac{1}{2}mv^2 = \frac{hc}{\lambda} - \phi$$

From this equation, it is clear that the velocity ($$v$$) of the emitted electrons is a direct function of the wavelength ($$\lambda$$) of the incident light. If the wavelength increases, the term $$hc/\lambda$$ decreases, leading to lower kinetic energy and thus lower velocity for the emitted electrons (provided $$hc/\lambda > \phi$$).

Analyzing the Options for Electron Velocity

Let's evaluate each given option regarding the velocity of electrons in the photoemission process:

  • Is a function of the wavelength of the incident light: As derived from Einstein's photoelectric equation, the maximum kinetic energy, and consequently the velocity of the emitted electrons, is indeed dependent on the wavelength of the incident light. This statement is consistent with the principles of the photoelectric effect.
  • Is directly proportional to light intensity: Light intensity, which refers to the number of photons striking the surface per unit area per unit time, affects the *number* of electrons emitted, not their individual maximum kinetic energy or velocity. A higher intensity means more photons, leading to more electrons being ejected, but each electron's maximum energy depends only on the energy of the individual photon (and the work function), not how many other photons are present.
  • Is a characteristic of the target material: While the work function $$\phi$$ is a characteristic of the target material and plays a role in determining the threshold energy for photoemission, the velocity of the emitted electrons is not *solely* a characteristic of the material. It also significantly depends on the energy (wavelength) of the incident light. Different wavelengths of light incident on the *same* material will result in electrons being emitted with different velocities.

Therefore, the velocity with which electrons are emitted in the photoemission process is a function of the wavelength of the incident light.

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Important Questions from Carriers in Semiconductors

  1. The process of adding impurities to a pure semiconductor is called

  2. Mobility and conductivity are related by which of the following equations?

  3. How many electrons are there in the valence shell of a pure semiconductor?

  4. In a pure silicon, what is the time for an electron to drift $1\mu m$ in an electric field of 100 V/cm? 

    Assume electron mobility of $1350 \text{ cm}^2/V-s$

  5. Match the LIST-I with LIST-II

    LIST-ILIST-II
    A. Einstein relationI. ${qD_n} \frac{dn}{dx}$
    B. Diffusion length of electronII. $\sqrt{D_n \tau_n}$
    C. Electron diffusion current densityIII. $\frac{D_n}{\mu_n} = \frac{KT}{q}$
    D. Electron Drift velocityIV. $\mu_n E$

    Choose the correct answer from the options given below:

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