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Question

The letters of the word EQUATION are arranged in such a way that all vowels as well as consonants are together. How many such arrangements are there?

This question was previously asked in
NDA 2 2024 GAT Question Paper (01-Sep-2024)
The correct answer is
1440

Arranging Letters of EQUATION: Vowels and Consonants Together

This problem involves finding the number of ways to arrange the letters of the word 'EQUATION' under a specific condition: all the vowels must stay together, and all the consonants must also stay together.

Identifying Vowels and Consonants

First, let's identify the vowels and consonants in the word EQUATION:

  • The word EQUATION has 8 distinct letters.
  • Vowels: E, U, A, I, O. There are 5 vowels.
  • Consonants: Q, T, N. There are 3 consonants.

Grouping Vowels and Consonants Together

The condition requires that all vowels are grouped together and all consonants are grouped together. We can think of these groups as single units:

  • Let the block of vowels be represented as [VVVVV].
  • Let the block of consonants be represented as [CCC].

Now, we need to arrange these two blocks. The possible arrangements of these blocks are:

  • [VVVVV] [CCC]
  • [CCC] [VVVVV]

There are 2 possible ways to arrange these two blocks.

Calculating Arrangements Within Each Group

Next, we calculate how many ways the letters can be arranged within each block:

  • Arranging the Vowels: The 5 vowels (E, U, A, I, O) can be arranged among themselves in \(5!\) ways.
    Calculation: \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\) ways.
  • Arranging the Consonants: The 3 consonants (Q, T, N) can be arranged among themselves in \(3!\) ways.
    Calculation: \(3! = 3 \times 2 \times 1 = 6\) ways.

Determining the Total Number of Arrangements

To find the total number of arrangements satisfying the condition, we use the multiplication principle. We multiply the number of ways to arrange the blocks by the number of ways to arrange the letters within each block:

Total Arrangements = (Ways to arrange the 2 blocks) \(\times\) (Ways to arrange vowels within their block) \(\times\) (Ways to arrange consonants within their block)

Total Arrangements = \(2! \times 5! \times 3!\)

Total Arrangements = \(2 \times 120 \times 6\)

Total Arrangements = \(1440\)

Therefore, there are 1440 distinct arrangements of the letters of the word EQUATION where all vowels are together and all consonants are together.

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Important Questions from Permutation and Combination

  1. The following figure is made with nine squares of length 1 cm each.
                                                                                                             

    A student is standing at point P. The total number of shortest paths to reach point Q from point P, if the student walks along the boundaries of the squares only, is:

  2. Consider the following statements (all the angles are measured in degrees) :
    1. If two supplementary angles are $4x + 40$ and $10x$, then $x$ is;
    2. The complementary angle of $\frac{4}{5} \times 45$ is :
    3. If two complementary angles are in the ratio of $4 : 5$, then the smallest angle is :
    Which of the following is correct?
    Codes:
    1   2   3

  3. There are 40 persons in a palace. If every person shakes hands with every other person, what will be the total number of handshakes?
  4. How many words can be formed with or without meaning by using all letters of the word DELHI?
  5. A rectangular wall is divided into four squares of equal size where there are two rows each having two squares. The top left square is coloured with green. If, including green, there are three colours available and each square is coloured using any one of these three colours such that no two adjacent squares get painted with the same colour; then how many colour combinations are possible ?

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