The question asks us to find the total number of four-digit natural numbers where all the digits used are even.
A natural number is a positive whole number (1, 2, 3, ...). A four-digit number is a natural number between 1000 and 9999, inclusive.
The digits that are considered even are: 0, 2, 4, 6, 8. There are 5 even digits in total.
Let's consider the four positions of a four-digit number:
We need to determine the number of choices for each place, keeping in mind the constraints:
To find the total number of such four-digit natural numbers, we multiply the number of choices for each digit together. This is based on the fundamental principle of counting.
Total count = (Choices for Thousands) \(\times\) (Choices for Hundreds) \(\times\) (Choices for Tens) \(\times\) (Choices for Units)
Total count = \(4 \times 5 \times 5 \times 5\)
Total count = \(4 \times (5^3)\)
Total count = \(4 \times 125\)
Total count = 500
Therefore, there are 500 four-digit natural numbers where all the digits are even.
If the number of selections of r as well as (n + r) things from 5n different things are equal, then what is the value of r?
The following figure is made with nine squares of length 1 cm each.

A student is standing at point P. The total number of shortest paths to reach point Q from point P, if the student walks along the boundaries of the squares only, is:
Consider the following statements (all the angles are measured in degrees) :
1. If two supplementary angles are $4x + 40$ and $10x$, then $x$ is;
2. The complementary angle of $\frac{4}{5} \times 45$ is :
3. If two complementary angles are in the ratio of $4 : 5$, then the smallest angle is :
Which of the following is correct?
Codes:
1 2 3
A rectangular wall is divided into four squares of equal size where there are two rows each having two squares. The top left square is coloured with green. If, including green, there are three colours available and each square is coloured using any one of these three colours such that no two adjacent squares get painted with the same colour; then how many colour combinations are possible ?