To determine how many 4-digit numbers exist where all the digits are odd, we need to identify the possible choices for each digit position in a 4-digit number.
An odd digit can be one of the following numbers: 1, 3, 5, 7, or 9. Therefore, for any digit position, there are 5 possible choices.
Let's analyze each of the digit positions in the 4-digit number:
Using the basic principle of counting, the total number of 4-digit numbers with all digits odd is the product of the number of choices for each digit place.
5 \times 5 \times 5 \times 5 = 5^4 = 625
Thus, there are 625 4-digit numbers where all digits are odd. Therefore, the correct answer is: 625.
If the number of selections of r as well as (n + r) things from 5n different things are equal, then what is the value of r?
The following figure is made with nine squares of length 1 cm each.

A student is standing at point P. The total number of shortest paths to reach point Q from point P, if the student walks along the boundaries of the squares only, is:
Consider the following statements (all the angles are measured in degrees) :
1. If two supplementary angles are $4x + 40$ and $10x$, then $x$ is;
2. The complementary angle of $\frac{4}{5} \times 45$ is :
3. If two complementary angles are in the ratio of $4 : 5$, then the smallest angle is :
Which of the following is correct?
Codes:
1 2 3
A rectangular wall is divided into four squares of equal size where there are two rows each having two squares. The top left square is coloured with green. If, including green, there are three colours available and each square is coloured using any one of these three colours such that no two adjacent squares get painted with the same colour; then how many colour combinations are possible ?