The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?
320 km
This problem involves two trains traveling towards each other from different stations. We need to find out where they meet. When two objects move towards each other, we can use the concept of relative speed to determine how quickly the distance between them decreases.
Here's what we know:
Since the two trains are moving towards each other, their speeds add up to find the rate at which the distance between them closes. This is called their relative speed.
Relative Speed = Speed of Train X + Speed of Train Y
\[ \text{Relative Speed} = 40 \, \text{km/h} + 60 \, \text{km/h} = 100 \, \text{km/h} \]This means the distance between the trains decreases by 100 km every hour.
The trains will meet when the entire distance between A and B (800 km) has been covered by their combined movement. We can find the time it takes using the total distance and the relative speed.
Time = Total Distance ÷ Relative Speed
\[ \text{Time} = \frac{800 \, \text{km}}{100 \, \text{km/h}} = 8 \, \text{hours} \]So, the two trains will meet 8 hours after they start traveling.
We need to find out how far from station A the trains meet. Since train X starts from A and travels towards B, the distance it covers in the 8 hours before meeting train Y will be the meeting point's distance from A.
Distance from A = Speed of Train X × Time
\[ \text{Distance from A} = 40 \, \text{km/h} \times 8 \, \text{hours} = 320 \, \text{km} \]Therefore, the trains will cross each other at a point 320 km away from station A.
Here is a quick summary of the steps:
| Quantity | Value | Calculation/Reason |
|---|---|---|
| Distance A to B | 800 km | Given |
| Speed of Train X (from A) | 40 km/h | Given |
| Speed of Train Y (from B) | 60 km/h | Given |
| Relative Speed | 100 km/h | \(40 + 60\) km/h (moving towards each other) |
| Time to Meet | 8 hours | \(800 \div 100\) hours |
| Distance from A (where they meet) | 320 km | \(40 \times 8\) km |
| Concept | Explanation | Formula (Simple Case) |
|---|---|---|
| Relative Speed (towards each other) | The sum of the speeds of two objects moving in opposite directions towards each other. It represents the rate at which the distance between them decreases. | \(V_{\text{relative}} = V_1 + V_2\) |
| Relative Speed (away from each other) | The sum of the speeds of two objects moving in opposite directions away from each other. It represents the rate at which the distance between them increases. | \(V_{\text{relative}} = V_1 + V_2\) |
| Relative Speed (same direction, faster chasing slower) | The difference between the speeds of two objects moving in the same direction. It represents the rate at which the distance between them changes (decreases if faster is behind). | \(V_{\text{relative}} = V_{\text{faster}} - V_{\text{slower}}\) |
| Distance, Speed, Time Relationship | Fundamental relationship in motion problems. | Distance = Speed × Time |
Relative motion is a crucial concept in physics and kinematics. It describes the motion of an object with respect to another object or a specific point of reference. In the train problem, we used the concept of relative speed because we were interested in how quickly the distance between the two moving trains changed.
When calculating relative speed:
Understanding relative motion helps simplify problems involving multiple moving bodies by allowing us to analyze the motion from a frame of reference attached to one of the bodies.
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