This problem asks us to find the capacity of a pond given its three dimensions: length, width, and depth. The capacity of an object like a pond typically refers to its volume, which is the amount of space it occupies or can hold.
The given dimensions of the pond are:
Since the pond has three distinct dimensions (length, width, depth), we can model it as a rectangular prism (or cuboid). The volume of a rectangular prism represents its capacity.
To find the capacity (volume) of the pond, we use the formula for the volume of a rectangular prism:
$$ V = l \times w \times h $$
Where:
Now, let's substitute the given dimensions into the formula:
$$ V = 20 \, \text{m} \times 14 \, \text{m} \times 6 \, \text{m} $$
First, multiply the length and width:
$$ 20 \times 14 = 280 $$
So, the area of the base is 280 square meters ($m^2$).
Next, multiply this area by the depth:
$$ V = 280 \, m^2 \times 6 \, \text{m} $$
$$ V = 1680 \, m^3 $$
The calculation shows that the volume of the pond is 1680 cubic meters ($m^3$). This represents the pond's capacity.
Comparing our calculated capacity with the given options:
Our calculated volume, 1680 $m^3$, matches the third option.
In a circular garden of radius 15 m, a path of 2 m wide has to be made inside the garden at the rate of ₹ 24 per sq. m. The cost of making the path is: (Take π = \(\frac{22}{7}\) )
A hollow cylinder with outer radius 4 cm and height 2 cm is made up of 1 cm thick metal sheet. What is the volume of metal used? (Take π = \(\frac{22}{7}\))
The length and breadth of a rectangular field are in the ratio 4 : 3. If the cost of cultivating the field at ₹2 per m 2is ₹600, then the length of the field is:
A cylindrical tank has a capacity of 5632 m3. If the diameter of its base is 8 m, what is the depth of the cylindrical tank? (Use π = \(\frac{22}{7}\))
Find the surface area of a sphere whose diameter is equal to 28 cm.