In a circular garden of radius 15 m, a path of 2 m wide has to be made inside the garden at the rate of ₹ 24 per sq. m. The cost of making the path is: (Take π = \(\frac{22}{7}\) )
₹4224
The problem asks us to find the cost of constructing a path inside a circular garden. We are given the radius of the garden, the width of the path, the rate per square meter for making the path, and the value of \(\pi\) to use.
The garden is circular with a radius of 15 m. A path 2 m wide is to be made inside the garden. This means the path forms an annular region (a ring) between two concentric circles.
To find the cost, we first need to calculate the area of the path. The area of the path is the area of the outer circle minus the area of the inner circle.
The area of a circle is given by the formula \(A = \pi \times (\text{radius})^2\).
The area of the path (\(A_{path}\)) is \(A_{outer} - A_{inner}\).
\[A_{path} = \pi R^2 - \pi r^2\]
We can factor out \(\pi\):
\[A_{path} = \pi (R^2 - r^2)\]
Now, substitute the values \(R=15\) m, \(r=13\) m, and \(\pi = \frac{22}{7}\):
\[A_{path} = \frac{22}{7} (15^2 - 13^2)\]
Calculate the squares:
\[A_{path} = \frac{22}{7} (225 - 169)\]
Subtract the values inside the parenthesis:
\[A_{path} = \frac{22}{7} (56)\]
Now, perform the multiplication. Since 56 is divisible by 7 (\(56 \div 7 = 8\)), we get:
\[A_{path} = 22 \times 8\]
\[A_{path} = 176 \text{ sq. m.}\]
The area of the circular path is 176 square meters.
The rate for making the path is given as ₹ 24 per square meter.
The total cost is the area of the path multiplied by the rate per square meter.
Total Cost = Area of path \(\times\) Rate per sq. m
Total Cost = \(176 \text{ sq. m} \times ₹ 24 \text{/sq. m}\)
\[\text{Total Cost} = 176 \times 24\]
Let's calculate \(176 \times 24\):
| 176 | |
|---|---|
| \(\times\) | 24 |
| --- | ---- |
| 704 (176 \(\times\) 4) | |
| + | 3520 (176 \(\times\) 20) |
| --- | ---- |
| 4224 |
The total cost of making the path is ₹ 4224.
The cost of making the 2 m wide path inside the circular garden of radius 15 m at the rate of ₹ 24 per sq. m is ₹ 4224.
| Item | Value/Formula | Description |
|---|---|---|
| Outer Radius (R) | 15 m | Radius of the garden |
| Path Width | 2 m | Width of the path inside the garden |
| Inner Radius (r) | R - Path Width = 15 - 2 = 13 m | Radius of the inner boundary of the path |
| Area of Outer Circle | \(\pi R^2\) | Area enclosed by the garden boundary |
| Area of Inner Circle | \(\pi r^2\) | Area of the garden excluding the path |
| Area of Path | \(\pi (R^2 - r^2)\) | Area of the annular region |
| \(\pi\) value | \(\frac{22}{7}\) | Value used for calculation |
| Path Area Calculation | \(\frac{22}{7} (15^2 - 13^2) = 176\) sq. m | Step-by-step calculation result |
| Cost Rate | ₹ 24 per sq. m | Cost to build path for one square meter |
| Total Cost | Path Area \(\times\) Rate | Total cost calculation |
| Final Cost | \(176 \times 24 = 4224\) | Resulting total cost in Rupees |
An annulus is the region between two concentric circles. In this problem, the circular path is an annulus. If the radius of the outer circle is \(R\) and the radius of the inner circle is \(r\), the area of the annulus is given by the formula:
\[\text{Area of Annulus} = \pi R^2 - \pi r^2 = \pi (R^2 - r^2)\]
This formula was used directly in our calculation. The term \(R^2 - r^2\) can also be factored as \((R-r)(R+r)\), which gives another way to express the area:
\[\text{Area of Annulus} = \pi (R-r)(R+r)\]
In our case, \(R=15\) and \(r=13\):
So, the area is \(\pi \times 2 \times 28 = 56\pi\).
Using \(\pi = \frac{22}{7}\):
\[\text{Area} = \frac{22}{7} \times 56 = 22 \times 8 = 176 \text{ sq. m}\]
This confirms the previous calculation method and shows an alternative way to calculate the area of the annular path.
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