A hollow cylinder with outer radius 4 cm and height 2 cm is made up of 1 cm thick metal sheet. What is the volume of metal used? (Take π = \(\frac{22}{7}\))
44 cm3
This question asks us to find the volume of metal used to create a hollow cylinder. A hollow cylinder is like a pipe; it has an outer boundary and an inner boundary, with the metal forming the region between them. To find the volume of the metal, we need to calculate the volume of the larger cylinder (including the hole) and subtract the volume of the inner, empty space (the hole).
We are given the following information about the hollow cylinder:
The thickness of the metal sheet is the difference between the outer radius and the inner radius. If the outer radius is \(R\) and the thickness is \(t\), the inner radius (\(r\)) can be found using the formula:
\(r = R - t\)
Substituting the given values:
\(r = 4 \text{ cm} - 1 \text{ cm}\)
\(r = 3 \text{ cm}\)
So, the inner radius of the hollow cylinder is 3 cm.
The volume of a solid cylinder is given by the formula \(V = \pi r_{cylinder}^2 h\). For a hollow cylinder, the volume of the material used is the difference between the volume of the outer cylinder and the volume of the inner cylinder.
Volume of outer cylinder (\(V_{outer}\)) = \(\pi R^2 h\)
Volume of inner cylinder (\(V_{inner}\)) = \(\pi r^2 h\)
Volume of metal used (\(V_{metal}\)) = \(V_{outer} - V_{inner} = \pi R^2 h - \pi r^2 h\)
We can factor out \(\pi h\) from the expression:
\(V_{metal} = \pi h (R^2 - r^2)\)
This is the standard formula for the volume of a hollow cylinder's material.
Now, let's substitute the values we have into the formula for the volume of metal:
\(R = 4\) cm, \(r = 3\) cm, \(h = 2\) cm, and \(\pi = \frac{22}{7}\)
\(V_{metal} = \frac{22}{7} \times 2 \times (4^2 - 3^2)\)
First, calculate the squares of the radii:
\(4^2 = 4 \times 4 = 16\)
\(3^2 = 3 \times 3 = 9\)
Now, substitute these values back into the equation:
\(V_{metal} = \frac{22}{7} \times 2 \times (16 - 9)\)
Calculate the difference inside the parentheses:
\(16 - 9 = 7\)
Substitute this difference back:
\(V_{metal} = \frac{22}{7} \times 2 \times 7\)
Now, perform the multiplication. We can cancel out the 7 in the denominator with the 7 in the numerator:
\(V_{metal} = 22 \times 2 \times \frac{7}{7}\)
\(V_{metal} = 22 \times 2 \times 1\)
\(V_{metal} = 44\)
The volume of metal used is 44 cubic centimeters.
The unit for volume is cubic centimeters (cm\(^3\)) because the dimensions are given in centimeters.
Let's check the calculated volume against the provided options:
| Option | Volume |
|---|---|
| 1 | 40 cm<sup>3</sup> |
| 2 | 56 cm<sup>3</sup> |
| 3 | 44 cm<sup>3</sup> |
| 4 | 65 cm<sup>3</sup> |
Our calculated volume is 44 cm\(^3\), which matches Option 3.
| Concept | Formula | Application in this problem |
|---|---|---|
| Inner Radius (\(r\)) | \(r = R - t\) (where \(R\) is outer radius, \(t\) is thickness) | \(r = 4 \text{ cm} - 1 \text{ cm} = 3 \text{ cm}\) |
| Volume of Solid Cylinder | \(V = \pi r_{cylinder}^2 h\) | Used to find volumes of outer and inner parts. |
| Volume of Metal in Hollow Cylinder | \(V_{metal} = \pi h (R^2 - r^2)\) | \(\frac{22}{7} \times 2 \times (4^2 - 3^2) = 44 \text{ cm}^3\) |
Cylinders are important shapes in geometry and appear in many real-world applications. Understanding how to calculate their volume and surface area is crucial.
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