To solve the problem of finding the number of pairs of natural numbers \( m \) and \( n \) (where \( m > n \)) such that the difference of their squares is 72, we start by using the formula for the difference of squares:
\(m^2 - n^2 = (m - n)(m + n) = 72\)
Here, we need to find integer solutions for pairs \( (m, n) \) where the product of \((m - n)\) and \((m + n)\) equals 72.
Step-by-step solution:
From the above calculations, the valid pairs are: (19, 17), (11, 7), and (9, 3). Therefore, there are 3 pairs of natural numbers that satisfy the given condition.
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