What is the sum of the largest and the smallest 4-digit numbers made by using single digit prime numbers (without repetition)?
This question asks us to find the sum of two specific 4-digit numbers. These numbers must be formed using only single-digit prime numbers, and importantly, each digit must be used only once (no repetition) within each number.
First, let's recall what prime numbers are. A prime number is a whole number greater than 1 that has only two divisors: 1 and itself. The single-digit numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
So, the set of single-digit prime numbers we can use is {2, 3, 5, 7}. We need to form 4-digit numbers using each of these digits exactly once.
To create the largest possible 4-digit number using the digits {2, 3, 5, 7} without repetition, we should arrange the digits in descending order from left to right (from the thousands place to the units place).
Therefore, the largest 4-digit number formed is 7532.
To create the smallest possible 4-digit number using the same digits {2, 3, 5, 7} without repetition, we should arrange the digits in ascending order from left to right.
Therefore, the smallest 4-digit number formed is 2357.
The final step is to find the sum of the largest number (7532) and the smallest number (2357).
We can perform the addition:
$ \begin{array}{@{}c@{\,}c@{}c@{}c@{}c} & 7 & 5 & 3 & 2 \\ + & 2 & 3 & 5 & 7 \\ \hline & 9 & 8 & 8 & 9 \\ \end{array} $
Alternatively, using standard notation:
Sum = Largest Number + Smallest Number
Sum = \(7532 + 2357\)
Sum = \(9889\)
The sum of the largest and smallest 4-digit numbers made by using single-digit prime numbers (2, 3, 5, 7) without repetition is 9889.
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