The cost of a diamond is directly proportional to the square of its weight. The cost of a 14 gm diamond is Rs. 2560. This diamond got broken down into two pieces in the ratio of 5 ∶ 9. How much loss percent is incurred due to this breakage ? (Correct to two decimal places)
45.92 percent
This problem deals with the concept of direct proportionality and calculating percentage loss when a valuable item like a diamond breaks. The key information is that the cost of the diamond is directly proportional to the square of its weight.
We are given that the cost (C) of the diamond is directly proportional to the square of its weight (W). Mathematically, this relationship can be written as:
$$ C \propto W^2 $$
To turn this proportionality into an equation, we introduce a constant of proportionality, let's call it 'k'.
$$ C = k \times W^2 $$
Here, k is a constant value that relates the cost and the square of the weight for a diamond of a specific quality.
We are given that a 14 gm diamond costs Rs. 2560. We can use this information to find the value of 'k'.
Substitute these values into the equation $C = k \times W^2$:
$$ 2560 = k \times (14)^2 $$
$$ 2560 = k \times 196 $$
Now, solve for 'k':
$$ k = \frac{2560}{196} $$
We can simplify this fraction by dividing both the numerator and the denominator by their common factors. Both are divisible by 4:
$$ k = \frac{2560 \div 4}{196 \div 4} = \frac{640}{49} $$
So, the proportionality constant $k = \frac{640}{49}$.
The original 14 gm diamond broke into two pieces with weights in the ratio 5 : 9. To find the weight of each piece, we first find the total number of parts in the ratio:
Total parts = 5 + 9 = 14 parts.
Since the total weight is 14 gm, each part of the ratio corresponds to 1 gm ($14 \text{ gm} / 14 \text{ parts} = 1 \text{ gm/part}$).
Let's verify: 5 gm + 9 gm = 14 gm, which is the original weight.
After the breakage, the value of the diamond is the sum of the values of the two pieces. We use the same proportionality relation $C = k \times W^2$ for each piece.
$$ C_1 = k \times W_1^2 = \frac{640}{49} \times (5)^2 = \frac{640}{49} \times 25 $$
$$ C_2 = k \times W_2^2 = \frac{640}{49} \times (9)^2 = \frac{640}{49} \times 81 $$
The total cost of the broken diamond ($C_{\text{broken}}$) is the sum of the costs of the two pieces:
$$ C_{\text{broken}} = C_1 + C_2 = \left(\frac{640}{49} \times 25\right) + \left(\frac{640}{49} \times 81\right) $$
We can factor out the common term $\frac{640}{49}$:
$$ C_{\text{broken}} = \frac{640}{49} \times (25 + 81) $$
$$ C_{\text{broken}} = \frac{640}{49} \times 106 $$
Now, calculate the value:
$$ C_{\text{broken}} = \frac{67840}{49} $$
Let's calculate the approximate value:
$$ C_{\text{broken}} \approx 1384.4898 $$
So, the total cost after breakage is approximately Rs. 1384.49.
The loss incurred is the difference between the original cost and the total cost after breakage.
Original Cost ($C_{\text{original}}$) = Rs. 2560
Cost After Breakage ($C_{\text{broken}}$) = Rs. $\frac{67840}{49}$
Loss = $C_{\text{original}} - C_{\text{broken}}$
$$ \text{Loss} = 2560 - \frac{67840}{49} $$
To subtract, find a common denominator (49):
$$ \text{Loss} = \frac{2560 \times 49 - 67840}{49} $$
$$ \text{Loss} = \frac{125440 - 67840}{49} $$
$$ \text{Loss} = \frac{57600}{49} $$
Let's calculate the approximate value:
$$ \text{Loss} \approx 1175.5102 $$
The loss incurred is approximately Rs. 1175.51.
The loss percentage is calculated with respect to the original cost.
$$ \text{Loss Percentage} = \left( \frac{\text{Loss}}{\text{Original Cost}} \right) \times 100 $$
$$ \text{Loss Percentage} = \left( \frac{57600/49}{2560} \right) \times 100 $$
$$ \text{Loss Percentage} = \left( \frac{57600}{49 \times 2560} \right) \times 100 $$
$$ \text{Loss Percentage} = \left( \frac{57600}{125440} \right) \times 100 $$
Now, perform the calculation:
$$ \text{Loss Percentage} \approx 0.45918 \times 100 $$
$$ \text{Loss Percentage} \approx 45.918 \text{ percent} $$
Rounding to two decimal places, the loss percentage is 45.92 percent.
| Description | Value |
|---|---|
| Original Weight | 14 gm |
| Original Cost | Rs. 2560 |
| Proportionality Constant (k) | $\frac{640}{49}$ |
| Ratio of Broken Pieces | 5 ∶ 9 |
| Weight of 1st piece | 5 gm |
| Weight of 2nd piece | 9 gm |
| Cost of 1st piece | $\frac{640}{49} \times 25$ |
| Cost of 2nd piece | $\frac{640}{49} \times 81$ |
| Total Cost After Breakage | $\frac{640}{49} \times 106$ or $\frac{67840}{49}$ |
| Total Loss | $\frac{57600}{49}$ |
| Loss Percentage (Approx) | 45.92% |
| Concept | Formula/Explanation |
|---|---|
| Direct Proportionality | If A is directly proportional to B, A ∝ B, or A = kB for some constant k. |
| Cost-Weight Relation | Cost ∝ (Weight)$^2$, i.e., C = k × W$^2$. |
| Ratio Division | To divide a quantity X in ratio a:b, the parts are $\frac{a}{a+b} \times X$ and $\frac{b}{a+b} \times X$. |
| Percentage Loss | $\frac{\text{Original Value} - \text{New Value}}{\text{Original Value}} \times 100$ |
Proportionality is a fundamental concept in mathematics and physics used to describe how quantities relate to each other. In direct proportionality, as one quantity increases, the other increases at a constant rate. In inverse proportionality, as one quantity increases, the other decreases.
Understanding proportionality helps in solving many problems involving scaling of quantities based on given relationships.
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