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Question

The angle of elevation of the top of a building at a distance of 70 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is \(70\sqrt 3 \) m

Calculating Building Height Using Angle of Elevation

This problem involves finding the height of a building using trigonometry, specifically the concept of the angle of elevation. We are given the distance from the foot of the building and the angle of elevation to the top of the building.

Understanding the Angle of Elevation Problem

The angle of elevation is the angle formed by the horizontal line of sight and the line of sight upwards to an object. In this case, the object is the top of the building. We can visualize this scenario as a right-angled triangle where:

  • The height of the building is the side opposite the angle of elevation.
  • The distance from the foot of the building is the side adjacent to the angle of elevation.
  • The line of sight from the observer's eye to the top of the building is the hypotenuse.

Applying Trigonometry to Find Height

In a right-angled triangle, the trigonometric ratio that relates the opposite side and the adjacent side is the tangent function (tan). The formula is:

\(\tan(\text{angle}) = \frac{\text{Opposite side}}{\text{Adjacent side}}\)

In our problem:

  • Angle of elevation = \(60^\circ\)
  • Adjacent side (Distance from foot) = 70 m
  • Opposite side (Height of the building) = Let's call it \(h\)

So, we can write the equation:

\(\tan(60^\circ) = \frac{h}{70}\)

Solving for the Height of the Building

To find the height \(h\), we need to multiply both sides of the equation by 70:

\(h = 70 \times \tan(60^\circ)\)

We know that the value of \(\tan(60^\circ)\) is \(\sqrt 3\).

Substituting this value into the equation:

\(h = 70 \times \sqrt 3\)

\(h = 70\sqrt 3 \text{ m}\)

Therefore, the height of the building is \(70\sqrt 3\) meters.

Step-by-Step Solution Summary

  1. Identify the given information: angle of elevation (\(60^\circ\)), distance from the foot (70 m).
  2. Recognize the problem forms a right-angled triangle.
  3. Identify the required side (height) as the opposite side and the given distance as the adjacent side to the angle of elevation.
  4. Choose the appropriate trigonometric ratio: tangent (\(\tan\)), which relates opposite and adjacent sides.
  5. Set up the equation: \(\tan(60^\circ) = \frac{\text{Height}}{70}\).
  6. Recall the value of \(\tan(60^\circ) = \sqrt 3\).
  7. Solve for the height: Height = \(70 \times \tan(60^\circ) = 70 \times \sqrt 3 = 70\sqrt 3\) m.

Revision Table: Common Trigonometric Values

Angle sin cos tan
\(30^\circ\) \(\frac{1}{2}\) \(\frac{\sqrt 3}{2}\) \(\frac{1}{\sqrt 3}\)
\(45^\circ\) \(\frac{1}{\sqrt 2}\) \(\frac{1}{\sqrt 2}\) 1
\(60^\circ\) \(\frac{\sqrt 3}{2}\) \(\frac{1}{2}\) \(\sqrt 3\)
\(90^\circ\) 1 0 Undefined

Additional Information: Angle of Elevation and Right Triangles

Angle of Elevation: This is an angle measured upwards from a horizontal line to a point above the observer. It's a key concept in solving problems involving heights and distances using trigonometry.

Right Triangles: A right-angled triangle is a triangle in which one of the angles is exactly \(90^\circ\). The sides of a right triangle have specific relationships defined by trigonometric ratios (sine, cosine, tangent), which are essential for solving problems like finding the height of a building or the distance to an object.

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Similar Questions

  1. A person standing at a distance looks at a building having a height of 1000 metres. The angle between the top of the building and the ground is 30°. At what approximate distance (in metres) is the person standing away from the building.

  2. Two ships are on the opposite of a light house such that all three of them are collinear. The angles of depression of the two ships from the top of the light house are 30° and 60°. If the ships are 230√3 m apart, then find the height of the light house (in m).

  3. From the top of an upright pole 17.75 m high, the angle of elevation of the top of an upright tower was 60⁰. If the tower was 57.75 m tall, how far away (in m) from the foot of the pole was the foot of the tower?

  4. From the top of an upright pole 24√3 feet high, the angle of elevation of the top of an upright tower was 60°. If the foot of the pole was 60 feet away from the foot of the tower, what tall (in feet) was the tower?

  5. The angle of elevation of the top of a tower from the top of a building whose height is 680 m is 45° and the angle of elevation of the top of same tower from the foot of the same building is 60°. What is the height (in m) of the tower?

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Important Questions from Heights and Distances

  1. Two ships are sailing in the sea on the two sides of a lighthouse. The angles of elevation of the top of the lighthouse as observed from the ships are 45 ° and 60° respectively. If the lighthouse is 81 m high, then the distance between two ships is:

  2. The horizontal distance between two towers is 40√3 m. The angle of depression of the top of the first tower when seen from the top of the second tower is 30°. If the height of the second tower is 130 m, find the height of the first tower.

  3. The angle of elevation of a ladder leaning against a house is 60° and the foot of the ladder is 6.5 metres from the house. The length of the ladder is

  4. A kite is flying at a height of 50 m. If the length of the string is 100 m then the inclination of the string to the horizontal ground in degree measures is:

    A. 90

    B. 45

    C. 60

    D. 30

  5. Two poles of the height 15 m and 20 m stand vertically upright on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.

    A. 11 m

    B. 12 m

    C. 13 m

    D. 14 m

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