A kite is flying at a height of 50 m. If the length of the string is 100 m then the inclination of the string to the horizontal ground in degree measures is: A. 90 B. 45 C. 60 D. 30
D
The problem describes a kite flying at a certain height with a given length of string. We need to find the angle that the kite string makes with the horizontal ground. This situation can be modeled using a right-angled triangle.
Imagine the following:
These three lines form a right-angled triangle where:
We are given:
We need to find the angle of inclination, let's call it $\theta$, which is the angle between the string and the horizontal ground.
In a right-angled triangle, the sine of an angle is defined as the ratio of the length of the opposite side to the length of the hypotenuse.
Mathematically, this is written as:
\(\text{sin}(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}\)
Substitute the given values into the sine formula:
\(\text{sin}(\theta) = \frac{50 \, \text{m}}{100 \, \text{m}}\)
\(\text{sin}(\theta) = \frac{1}{2}\)
To find the angle \(\theta\), we need to find the inverse sine (arcsin or $\text{sin}^{-1}$) of \(\frac{1}{2}\).
\(\theta = \text{sin}^{-1}\left(\frac{1}{2}\right)\)
We need to recall the standard trigonometric values for common angles. The angle whose sine is \(\frac{1}{2}\) is 30 degrees.
\(\theta = 30^\circ\)
Thus, the inclination of the kite string to the horizontal ground is 30 degrees.
Let's compare our calculated angle with the given options:
Our calculated angle is 30°, which matches option D.
The problem involves a right triangle formed by the kite's height, the string, and the ground. Using the given height (opposite side) and string length (hypotenuse), we used the sine function to find the angle of inclination. \(\text{sin}(\theta) = \frac{50}{100} = \frac{1}{2}\). The angle whose sine is $\frac{1}{2}$ is 30 degrees.
| Measurement | Value | Triangle Side |
|---|---|---|
| Kite Height | 50 m | Opposite |
| String Length | 100 m | Hypotenuse |
| Angle of Inclination ($\theta$) | ? | Angle |
| Trigonometric Ratio | Formula |
|---|---|
| Sine ($\text{sin}$) | \(\frac{\text{Opposite}}{\text{Hypotenuse}}\) |
| Cosine ($\text{cos}$) | \(\frac{\text{Adjacent}}{\text{Hypotenuse}}\) |
| Tangent ($\text{tan}$) | \(\frac{\text{Opposite}}{\text{Adjacent}}\) |
| Angle ($\theta$) | sin($\theta$) |
|---|---|
| 0° | 0 |
| 30° | \(\frac{1}{2}\) |
| 45° | \(\frac{1}{\sqrt{2}}\) or \(\frac{\sqrt{2}}{2}\) |
| 60° | \(\frac{\sqrt{3}}{2}\) |
| 90° | 1 |
The angle of inclination of the kite string to the horizontal ground is also known as the angle of elevation from the point on the ground to the kite. The angle of elevation is the angle formed by the horizontal line and the line of sight to an object above the horizontal line. In this case, the horizontal line is the ground, and the line of sight is the kite string.
Understanding angles of elevation and depression is crucial in solving problems involving heights and distances using trigonometry.
This problem demonstrates a practical application of basic trigonometry, specifically the sine ratio, in calculating angles in real-world scenarios.
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