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Question

The altitudes of two similar triangles are 4 cm and 6 cm. If the area of the larger triangle is $36\text{ cm}^2$, what will be the area of the other one?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper PDF (31-Jan-2021) (Shift 1)
The correct answer is
$16\text{ cm}^2$

Similar Triangles Area Ratio Concept

In similar triangles, the ratio of their areas is equivalent to the square of the ratio of their corresponding altitudes (or sides, medians, etc.).

Calculating Triangle Areas using Altitudes

This principle allows us to find the area of one similar triangle if we know the area of another and the ratio of their corresponding altitudes.

Problem Details for Similar Triangles

  • Given altitudes: $h_1 = 4\text{ cm}$ and $h_2 = 6\text{ cm}$.
  • Given area of the larger triangle: $A_2 = 36\text{ cm}^2$.
  • We need to find the area of the other triangle, $A_1$.

Step-by-Step Area Calculation

  1. Ratio of Altitudes: Determine the ratio between the altitudes. Since $4\text{ cm} < 6\text{ cm}$, $h_1$ corresponds to the smaller triangle and $h_2$ to the larger one. $ \frac{h_1}{h_2} = \frac{4\text{ cm}}{6\text{ cm}} = \frac{2}{3} $
  2. Square of Altitude Ratio: Square this ratio to find the ratio of the areas. $ \left(\frac{h_1}{h_2}\right)^2 = \left(\frac{2}{3}\right)^2 = \frac{4}{9} $ This establishes the area relationship: $\frac{A_1}{A_2} = \frac{4}{9}$.
  3. Calculate Unknown Area: Use the area ratio and the known area of the larger triangle ($A_2 = 36\text{ cm}^2$) to find the area of the other triangle ($A_1$). $ A_1 = \frac{4}{9} \times A_2 $ $ A_1 = \frac{4}{9} \times 36\text{ cm}^2 $ $ A_1 = 4 \times \frac{36}{9}\text{ cm}^2 $ $ A_1 = 4 \times 4\text{ cm}^2 $ $ A_1 = 16\text{ cm}^2 $

Final Area Calculation Result

The area of the other triangle is $16\text{ cm}^2$.

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Similar Questions

  1. In $\Delta ABC$ $\overline{PQ} \parallel \overline{AB}$. P and Q are on BC and CA respectively. If CQ : QA = 1 : 3 and CP = 4, then what is the value of BC?
  2. The perimeters of two similar triangles $\Delta\text{XYZ}$ and $\Delta\text{LMN}$ are $48\text{ cm}$ and $32\text{ cm}$ respectively. If $\text{LM} = 12\text{ cm}$, then what is the length of XY?
  3. In $\Delta$ABC, DE||BC, intersecting AB at D and AC at E. AD : BD :: 2 : 3 and the area of trapezium BDEC is $63 \text{ cm}^2$. What is the area of $\Delta$ADE?
  4. In the given figure, \(HI\), \(GF\), and \(DE\) are parallel lines. If \(DG = 6\), \(GH = 4\), and \(FI = 8\), then \(EF = ?\)

  5. The lengths of the three sides of \(\Delta ABC\) are 6 cm, 4 cm, and 9 cm. Another triangle \(\Delta DEF\) is similar to \(\Delta ABC\), one side of which is 36 cm. What is the largest possible perimeter of \(\Delta DEF\)?


Important Questions from Triangles, Congruence and Similarity

  1. In a $\Delta ABC$, $\angle C = (9/4) \angle B = (3/2) (\angle A+\angle B)$. Find the measure of the angles.

  2. The areas of two similar triangles $\Delta$XYZ and $\Delta$LMN are 49 cm$^2$ and 9 cm$^2$, respectively. If LM = 9 cm, then the length of XY is:
  3. Triangles \(PQR\) and \(ABC\) are similar triangles. Triangle \(ABC\) have the following sides 

    \(AB = 12 \text{ cm}\), 

    \(AC = 15 \text{ cm}\), 

    \(CB = 21 \text{ cm}\). 

    Triangle \(PQR\) have the following sides: 

    \(PQ = 4 \text{ cm}\), 

    \(RQ = 7 \text{ cm}\). 

    What is the length of side \(PR\)?

  4. For a pair of similar triangles, the angles made at \(Q\) is same in both the triangles \(PQR\) and \(LQJ\).

    If the length of side \(QJ\) is 10 cm and \(QR\) is 5 cm, what is the ratio of their total areas?

  5. In $\Delta ABC$ $\overline{PQ} \parallel \overline{AB}$. P and Q are on BC and CA respectively. If CQ : QA = 1 : 3 and CP = 4, then what is the value of BC?
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