Study the following table and answer the question that follows. A school has four sections A, B, C and D of Class IX students. The results of Science and Mathematics examinations are shown in the following table. RESULT No. of Students Section A Section B Section C Section D Failed in both 24 25 18 20 Failed in Science but passed in Mathematics 14 12 10 15 Passed in Science but failed in Mathematics 7 6 8 10 Passed in both 63 60 56 55
What percentage of students of section C Passed in Science but failed in Mathematics?
8.70%
The question asks for the percentage of students in Section C who passed in Science but failed in Mathematics based on the provided table showing the results of Science and Mathematics examinations for Class IX students across four sections (A, B, C, and D).
Let's extract the relevant data for Section C from the table:
The total number of students in Section C is the sum of students in all these categories.
Total students in Section C = (Failed in both) + (Failed in Science but passed in Maths) + (Passed in Science but failed in Maths) + (Passed in both)
\( \text{Total students in Section C} = 18 + 10 + 8 + 56 \)
\( \text{Total students in Section C} = 92 \)
We need to find the percentage of students who Passed in Science but failed in Mathematics in Section C. From the data extracted, the number of students in Section C who Passed in Science but failed in Mathematics is 8.
The percentage is calculated using the formula:
\( \text{Percentage} = \left( \frac{\text{Number of students who Passed in Science but failed in Mathematics}}{\text{Total number of students in Section C}} \right) \times 100 \)
Substituting the values for Section C:
\( \text{Percentage for Section C} = \left( \frac{8}{92} \right) \times 100 \)
\( \text{Percentage for Section C} \approx 0.0869565 \times 100 \)
\( \text{Percentage for Section C} \approx 8.69565 \% \)
Rounding the percentage to two decimal places gives 8.70%.
The percentage of students of Section C who Passed in Science but failed in Mathematics is approximately 8.70%.
| Section | Failed in both | Failed in Science but passed in Maths | Passed in Science but failed in Maths | Passed in both | Total Students |
|---|---|---|---|---|---|
| A | 24 | 14 | 7 | 63 | 108 |
| B | 25 | 12 | 6 | 60 | 103 |
| C | 18 | 10 | 8 | 56 | 92 |
| D | 20 | 15 | 10 | 55 | 100 |
Based on the calculations, 8.70% of students in Section C passed in Science but failed in Mathematics.
| Concept | Description | Formula |
|---|---|---|
| Percentage | A way to express a number as a fraction of 100. | \( \frac{\text{Part}}{\text{Whole}} \times 100 \) |
| Total/Whole | The entire amount or number in a set. | Sum of all parts |
| Part | A specific portion or number within the whole. | Specific category count |
Exam result tables like this provide valuable insights into student performance. We can use the data to calculate various percentages, such as:
To find the percentage of students who passed in Science in Section C, for example, you would add the number of students who Passed in Science but failed in Maths (8) and those who Passed in both (56), and divide by the total students in Section C (92), then multiply by 100.
\( \text{Passed in Science (Section C)} = \frac{8 + 56}{92} \times 100 = \frac{64}{92} \times 100 \approx 69.57\% \)
Understanding how to read and interpret data from tables is a fundamental skill in data analysis and statistics.
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
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| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?
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Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
A = Total number of cars manufactured by all the companies.
K = Difference between the number of C3 type cars manufactured by company H and the number of B3 type bike manufactured by company E.
What is the value of A : K?
H = Total number of B2 type bike manufactured by all the companies.
R = Total number of C1 type car manufactured by company F, G and D together.
What is the value of H / R?
What is the difference between the total number of C3 type car manufactured by company E and G together and the number of bikes of type B1 manufactured by company H?
What is the average of the total number of cars of type C1 manufactured by the given 5 companies?
Total number of bikes manufactured by company D is what percentage of total number of cars of type C1 manufacture by company G?
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Years | Production (in 1000 tonnes) | Sale (in 1000 tonnes) |
2015 | 1250 | 1000 |
2016 | 1400 | 1290 |
2017 | 1450 | 1100 |
2018 | 1500 | 1450 |
2019 | 1600 | 1390 |
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Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
What is the ratio of total number of patients recovered from covid-19 in April to total number of patients recovered from covid-19 in March?
In which state, the number of patients who recovered from covid-19 steadily decreasing?
What is the average number of patients who recovered from Covid-19 in Madhya Pradesh in four months?
Find the difference between the total number of patients recovered from Covid-19 in all months in Punjab and the total number of patients recovered from Covid-19 in all months in Rajasthan.
In February 2021 the number of patients recovered from Covid-19 in Punjab is how much approximant percent more/less than the number of patients recovered from Covid-19 Uttar Pradesh in the same month?