Study the following table and answer the question that follows. A school has four sections A, B, C and D of Class IX students. The results of Science and Mathematics examinations are shown in the following table. RESULT No. of Students Section A Section B Section C Section D Failed in both 24 25 18 20 Failed in Science but passed in Mathematics 14 12 10 15 Passed in Science but failed in Mathematics 7 6 8 10 Passed in both 63 60 56 55
What percentage of students of section C Passed in Science but failed in Mathematics?
8.70%
Calculating Percentage of Students in Section C Exam Results
The question asks for the percentage of students in Section C who passed in Science but failed in Mathematics based on the provided table showing the results of Science and Mathematics examinations for Class IX students across four sections (A, B, C, and D).
Analyzing the Data for Section C
Let's extract the relevant data for Section C from the table:
- Failed in both Science and Mathematics: 18 students
- Failed in Science but passed in Mathematics: 10 students
- Passed in Science but failed in Mathematics: 8 students
- Passed in both Science and Mathematics: 56 students
The total number of students in Section C is the sum of students in all these categories.
Total students in Section C = (Failed in both) + (Failed in Science but passed in Maths) + (Passed in Science but failed in Maths) + (Passed in both)
\( \text{Total students in Section C} = 18 + 10 + 8 + 56 \)
\( \text{Total students in Section C} = 92 \)
We need to find the percentage of students who Passed in Science but failed in Mathematics in Section C. From the data extracted, the number of students in Section C who Passed in Science but failed in Mathematics is 8.
Calculating the Required Percentage
The percentage is calculated using the formula:
\( \text{Percentage} = \left( \frac{\text{Number of students who Passed in Science but failed in Mathematics}}{\text{Total number of students in Section C}} \right) \times 100 \)
Substituting the values for Section C:
\( \text{Percentage for Section C} = \left( \frac{8}{92} \right) \times 100 \)
\( \text{Percentage for Section C} \approx 0.0869565 \times 100 \)
\( \text{Percentage for Section C} \approx 8.69565 \% \)
Rounding the percentage to two decimal places gives 8.70%.
Final Answer Derivation
The percentage of students of Section C who Passed in Science but failed in Mathematics is approximately 8.70%.
| Section | Failed in both | Failed in Science but passed in Maths | Passed in Science but failed in Maths | Passed in both | Total Students |
|---|---|---|---|---|---|
| A | 24 | 14 | 7 | 63 | 108 |
| B | 25 | 12 | 6 | 60 | 103 |
| C | 18 | 10 | 8 | 56 | 92 |
| D | 20 | 15 | 10 | 55 | 100 |
Based on the calculations, 8.70% of students in Section C passed in Science but failed in Mathematics.
Revision Table: Key Concepts in Percentage Calculation
| Concept | Description | Formula |
|---|---|---|
| Percentage | A way to express a number as a fraction of 100. | \( \frac{\text{Part}}{\text{Whole}} \times 100 \) |
| Total/Whole | The entire amount or number in a set. | Sum of all parts |
| Part | A specific portion or number within the whole. | Specific category count |
Additional Information: Analyzing Exam Results Data
Exam result tables like this provide valuable insights into student performance. We can use the data to calculate various percentages, such as:
- Percentage of students who passed in a specific subject (e.g., Science).
- Percentage of students who failed in a specific subject (e.g., Mathematics).
- Percentage of students who passed both subjects.
- Percentage of students who failed at least one subject.
To find the percentage of students who passed in Science in Section C, for example, you would add the number of students who Passed in Science but failed in Maths (8) and those who Passed in both (56), and divide by the total students in Section C (92), then multiply by 100.
\( \text{Passed in Science (Section C)} = \frac{8 + 56}{92} \times 100 = \frac{64}{92} \times 100 \approx 69.57\% \)
Understanding how to read and interpret data from tables is a fundamental skill in data analysis and statistics.
Similar Questions
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015
2015-2016
2016-0217
2017-2018
2018-2019
625
690
725
775
815
The period which has the maximum percentage increase in profit over the previous year is:
A = Total number of cars manufactured by all the companies.
K = Difference between the number of C3 type cars manufactured by company H and the number of B3 type bike manufactured by company E.
What is the value of A : K?
H = Total number of B2 type bike manufactured by all the companies.
R = Total number of C1 type car manufactured by company F, G and D together.
What is the value of H / R?
What is the difference between the total number of C3 type car manufactured by company E and G together and the number of bikes of type B1 manufactured by company H?
What is the average of the total number of cars of type C1 manufactured by the given 5 companies?
Total number of bikes manufactured by company D is what percentage of total number of cars of type C1 manufacture by company G?
Study the following table and answer the question:
Percentage of marks obtained by six students in five subjects A, B, C, D & E.
Students
Subject
A
(out of 75)
B
(out of 80)
C
(out of 100)
D
(out of 50)
E
(out of 150)
Manju
68
85
86
72
92
Amit
64
65
80
96
80
Rekha
88
75
65
74
90
Anuj
80
55
68
66
84
Abhi
72
65
72
54
74
Vikram
60
70
73
84
86
Total marks obtained by Amit, Abhi, and Anuj in subject E is what percent more than the total marks obtained by all the six students in subject B? (correct to one decimal place)Table shows the number of trees planted in 4 cities from 2016 to 2020.
Years
Chandigarh
Ahmadabad
Pune
Kolkata
2016
1800
2500
1800
2000
2017
2500
2300
1850
1800
2018
2300
2400
1840
1760
2019
2440
1950
1900
1600
2020
2250
2100
2000
1750
From 2016 to 2020, how many more trees were planted in Ahmedabad as compared to trees planted in Pune?Study the following table and answer the question:
Number of student Appeared (A) and Passed (P) in an annual examination from schools Q, R, S & T in five years (2014 to 2018)
Year
Schools
Q
R
S
T
A
P
A
P
A
P
A
P
2014
320
240
400
340
420
273
250
225
2015
400
320
380
285
350
280
300
228
2016
440
286
360
288
330
264
320
256
2017
350
252
420
294
380
247
350
315
2018
375
320
450
405
400
344
375
300
The total number of students passed from school Q in 2014 and 2018 is what percent less than the total number of students appeared from school R and S in 2017?The table shows the daily income (in Rs.) of 50 persons.
Study the table and answer the question:
Income (Rs)
No. of persons
Less than 200
12
Less than 250
26
Less than 300
34
Less than 350
40
Less than 400
50
How many persons earn Rs. 200 or more but less than Rs. 300?
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In which state, the number of patients who recovered from covid-19 steadily decreasing?
What is the average number of patients who recovered from Covid-19 in Madhya Pradesh in four months?
Find the difference between the total number of patients recovered from Covid-19 in all months in Punjab and the total number of patients recovered from Covid-19 in all months in Rajasthan.
In February 2021 the number of patients recovered from Covid-19 in Punjab is how much approximant percent more/less than the number of patients recovered from Covid-19 Uttar Pradesh in the same month?
