sinθ.cos(90° - θ) + cosθ.sin(90° - θ) = ?
1
The problem asks us to simplify the trigonometric expression: \(\sin\theta \cdot \cos(90^\circ - \theta) + \cos\theta \cdot \sin(90^\circ - \theta)\).
To solve this, we can use fundamental trigonometric identities. There are a couple of ways to approach this, both relying on key identities.
Recall the complementary angle identities:
Let's substitute these identities into the given expression:
Original expression: \(\sin\theta \cdot \cos(90^\circ - \theta) + \cos\theta \cdot \sin(90^\circ - \theta)\)
Substitute the identities:
\(\sin\theta \cdot (\sin\theta) + \cos\theta \cdot (\cos\theta)\)
This simplifies to:
\(\sin^2\theta + \cos^2\theta\)
Now, recall the Pythagorean identity:
Therefore, the expression simplifies to 1.
Another approach is to recognize the form of the expression. The given expression \(\sin\theta \cdot \cos(90^\circ - \theta) + \cos\theta \cdot \sin(90^\circ - \theta)\) matches the form of the sum of angles identity for sine:
In our expression, if we let \(A = \theta\) and \(B = 90^\circ - \theta\), the expression is exactly \(\sin A \cos B + \cos A \sin B\).
Using the identity, the expression is equal to \(\sin(A+B)\). Substitute the values of \(A\) and \(B\):
\(\sin(\theta + (90^\circ - \theta))\)
Simplify the angle inside the sine function:
\(\sin(\theta + 90^\circ - \theta) = \sin(90^\circ)\)
The value of \(\sin(90^\circ)\) is a standard trigonometric value:
Thus, using the sum of angles identity also shows that the expression simplifies to 1.
We simplified the expression \(\sin\theta \cdot \cos(90^\circ - \theta) + \cos\theta \cdot \sin(90^\circ - \theta)\) using trigonometric identities.
Alternatively:
Both methods confirm the result is 1.
| Identity Used | Formula |
|---|---|
| Complementary Angle (Cosine) | \(\cos(90^\circ - \theta) = \sin\theta\) |
| Complementary Angle (Sine) | \(\sin(90^\circ - \theta) = \cos\theta\) |
| Pythagorean Identity | \(\sin^2\theta + \cos^2\theta = 1\) |
| Sum of Angles (Sine) | \(\sin(A+B) = \sin A \cos B + \cos A \sin B\) |
Mastering trigonometric identities is crucial for simplifying expressions and solving trigonometric equations. Here's a quick table of commonly used identities.
| Category | Identity |
|---|---|
| Reciprocal Identities | \(\csc\theta = \frac{1}{\sin\theta}\), \(\sec\theta = \frac{1}{\cos\theta}\), \(\cot\theta = \frac{1}{\tan\theta}\) |
| Quotient Identities | \(\tan\theta = \frac{\sin\theta}{\cos\theta}\), \(\cot\theta = \frac{\cos\theta}{\sin\theta}\) |
| Pythagorean Identities | \(\sin^2\theta + \cos^2\theta = 1\), \(1 + \tan^2\theta = \sec^2\theta\), \(1 + \cot^2\theta = \csc^2\theta\) |
| Complementary Angle Identities | \(\sin(90^\circ - \theta) = \cos\theta\), \(\cos(90^\circ - \theta) = \sin\theta\), \(\tan(90^\circ - \theta) = \cot\theta\), etc. |
| Sum/Difference Identities | \(\sin(A \pm B) = \sin A \cos B \pm \cos A \sin B\) \(\cos(A \pm B) = \cos A \cos B \mp \sin A \sin B\) |
Simplifying trigonometric expressions is a common task in trigonometry. It often involves transforming a complex expression into a simpler one using known identities and algebraic manipulation. This skill is essential for solving trigonometric equations, evaluating integrals in calculus, and analyzing periodic functions.
When simplifying, look for:
Practice is key to becoming proficient in recognizing which identity to use in different situations.
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