If Tan θ = 7/24, then what is the value of p in (tanθ - secθ)/sinθ = -p/28 ?
75
The question asks us to find the value of 'p' in a given trigonometric equation. We are provided with the value of $\tan \theta$ and a relationship involving $\tan \theta$, $\sec \theta$, and $\sin \theta$. To solve this, we first need to find the values of $\sin \theta$ and $\sec \theta$ using the given value of $\tan \theta$.
Given that $\tan \theta = 7/24$. In a right-angled triangle, $\tan \theta$ is defined as the ratio of the opposite side to the adjacent side. So, we can consider the opposite side as 7 units and the adjacent side as 24 units.
Using the Pythagorean theorem, we can find the hypotenuse (h):
$\text{hypotenuse}^2 = \text{opposite}^2 + \text{adjacent}^2$
$h^2 = 7^2 + 24^2$
$h^2 = 49 + 576$
$h^2 = 625$
$h = \sqrt{625}$
$h = 25$
Now that we have all three sides of the right triangle (opposite = 7, adjacent = 24, hypotenuse = 25), we can find $\sin \theta$ and $\cos \theta$:
Next, we can find $\sec \theta$, which is the reciprocal of $\cos \theta$:
Let's summarize the trigonometric ratios we found:
| Ratio | Value |
|---|---|
| $\tan \theta$ | $7/24$ |
| $\sin \theta$ | $7/25$ |
| $\cos \theta$ | $24/25$ |
| $\sec \theta$ | $25/24$ |
The given equation is $(\tan \theta - \sec \theta) / \sin \theta = -p/28$. We will substitute the values we found for $\tan \theta$, $\sec \theta$, and $\sin \theta$ into this equation.
$\frac{\frac{7}{24} - \frac{25}{24}}{\frac{7}{25}} = \frac{-p}{28}$
First, simplify the numerator on the left side:
$\frac{7}{24} - \frac{25}{24} = \frac{7 - 25}{24} = \frac{-18}{24}$
The fraction $\frac{-18}{24}$ can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 6:
$\frac{-18 \div 6}{24 \div 6} = \frac{-3}{4}$
Now, substitute this back into the left side of the equation:
$\frac{-3/4}{7/25}$
To divide by a fraction, we multiply by its reciprocal:
$\frac{-3}{4} \times \frac{25}{7} = \frac{-3 \times 25}{4 \times 7} = \frac{-75}{28}$
Now the equation becomes:
$\frac{-75}{28} = \frac{-p}{28}$
To find the value of p, we can multiply both sides of the equation by 28:
$\frac{-75}{28} \times 28 = \frac{-p}{28} \times 28$
$-75 = -p$
Multiply both sides by -1:
$-75 \times (-1) = -p \times (-1)$
$75 = p$
So, the value of p is 75.
The calculated value of p is 75, which matches one of the provided options.
| Concept | Description | Formula/Example |
|---|---|---|
| Tan $\theta$ | Ratio of opposite side to adjacent side in a right triangle. | $\tan \theta = \text{Opposite} / \text{Adjacent}$ |
| Sin $\theta$ | Ratio of opposite side to hypotenuse in a right triangle. | $\sin \theta = \text{Opposite} / \text{Hypotenuse}$ |
| Sec $\theta$ | Reciprocal of Cos $\theta$. | $\sec \theta = 1 / \cos \theta = \text{Hypotenuse} / \text{Adjacent}$ |
| Pythagorean Theorem | Relates the sides of a right triangle. | $a^2 + b^2 = c^2$ |
Beyond the basic ratios derived from a right triangle, trigonometry involves various identities that relate these functions. Some fundamental identities are:
These identities are useful for simplifying expressions and solving more complex trigonometric equations.
If cosecx + cotx = 2, then cosecx = ?
If cosecθ + cotθ = 2, then cotθ = ?
If sin θ = 12/13, then find the value of 2cot θ + 13cos θ.
If tanα = √2 – 1, then the value of tanα – cotα = ?
sinθ.cos(90° - θ) + cosθ.sin(90° - θ) = ?
If sinx + cosx = √2sinx, then the value of tanx is:
If secθ + tanθ = 2, then secθ – tanθ = ?
If 3 tan θ = 2, find the value of \(\frac{2 \sin\theta-\cos\theta}{2 \cos\theta-\sin\theta}\).
sin 4A - cos 4A = 1, then A/2, in degree, is (0 < A ≤ 90°) -
What is the ratio of the greatest to the smallest value of 2 – 2 sin x – sin 2x, 0 ≤ x ≤ (π/2)?
If sinθ = \(\frac{4}{5}\) , Find the value of sin3θ
If x, y are acute angles, where 0 < x + y < 90° and sin(3x - 40°) = cos (3y + 40°), then the value of tan (x + y) is equal to
What is (1 + cot θ - cosec θ)(1 + tan θ + sec θ) equal to?
If cos x = p/q and 0° < x < 90°, then the value of tan x is: