If 3 tan θ = 2, find the value of \(\frac{2 \sin\theta-\cos\theta}{2 \cos\theta-\sin\theta}\).
The question asks us to find the value of a specific trigonometric expression involving \(\sin\theta\) and \(\cos\theta\), given a condition involving \(\tan\theta\). The given condition is \(3 \tan \theta = 2\), and the expression to evaluate is \(\frac{2 \sin\theta-\cos\theta}{2 \cos\theta-\sin\theta}\).
The condition \(3 \tan \theta = 2\) can be easily rewritten to find the value of \(\tan\theta\).
From \(3 \tan \theta = 2\), we get:
\[ \tan \theta = \frac{2}{3} \]
This value of \(\tan\theta\) is key to solving the problem.
We need to find the value of the expression \(\frac{2 \sin\theta-\cos\theta}{2 \cos\theta-\sin\theta}\). Notice that this expression contains both \(\sin\theta\) and \(\cos\theta\). Since we know the value of \(\tan\theta\) and we know that \(\tan\theta = \frac{\sin\theta}{\cos\theta}\), we can transform the given expression into terms of \(\tan\theta\). This is a common technique when dealing with expressions involving a mix of \(\sin\theta\) and \(\cos\theta\) and a known value for \(\tan\theta\).
To do this, we can divide both the numerator and the denominator of the expression by \(\cos\theta\). We must be careful here, assuming \(\cos\theta \ne 0\). If \(\cos\theta = 0\), then \(\theta\) would be \(90^\circ\) or \(270^\circ\) (or \(90^\circ + n \cdot 180^\circ\)), making \(\tan\theta\) undefined. Since \(\tan\theta\) is given as \(\frac{2}{3}\), \(\cos\theta\) cannot be zero.
The expression is: \(\frac{2 \sin\theta-\cos\theta}{2 \cos\theta-\sin\theta}\)
Divide the numerator by \(\cos\theta\):
\[ \frac{2 \sin\theta-\cos\theta}{\cos\theta} = \frac{2 \sin\theta}{\cos\theta} - \frac{\cos\theta}{\cos\theta} = 2 \tan\theta - 1 \]
Divide the denominator by \(\cos\theta\):
\[ \frac{2 \cos\theta-\sin\theta}{\cos\theta} = \frac{2 \cos\theta}{\cos\theta} - \frac{\sin\theta}{\cos\theta} = 2 - \tan\theta \]
So, the original expression can be rewritten as:
\[ \frac{2 \tan\theta - 1}{2 - \tan\theta} \]
We found earlier that \(\tan \theta = \frac{2}{3}\). Now, substitute this value into the transformed expression:
\[ \text{Value} = \frac{2 \left(\frac{2}{3}\right) - 1}{2 - \left(\frac{2}{3}\right)} \]
Perform the calculations:
\[ \text{Value} = \frac{\frac{4}{3} - 1}{2 - \frac{2}{3}} \]
To simplify the numerator and denominator, find a common denominator (which is 3):
\[ \text{Value} = \frac{\frac{4}{3} - \frac{3}{3}}{\frac{6}{3} - \frac{2}{3}} \]
\[ \text{Value} = \frac{\frac{4-3}{3}}{\frac{6-2}{3}} \]
\[ \text{Value} = \frac{\frac{1}{3}}{\frac{4}{3}} \]
To divide the fractions, multiply the numerator fraction by the reciprocal of the denominator fraction:
\[ \text{Value} = \frac{1}{3} \times \frac{3}{4} \]
\[ \text{Value} = \frac{1 \times 3}{3 \times 4} = \frac{3}{12} \]
Simplify the fraction:
\[ \text{Value} = \frac{1}{4} \]
Therefore, the value of the expression \(\frac{2 \sin\theta-\cos\theta}{2 \cos\theta-\sin\theta}\) is \(\frac{1}{4}\).
| Step | Action | Result |
|---|---|---|
| 1 | Solve for \(\tan\theta\) | \(\tan\theta = \frac{2}{3}\) |
| 2 | Rewrite expression using \(\tan\theta\) (divide by \(\cos\theta\)) | \(\frac{2 \tan\theta - 1}{2 - \tan\theta}\) |
| 3 | Substitute \(\tan\theta = \frac{2}{3}\) | \(\frac{2(\frac{2}{3}) - 1}{2 - \frac{2}{3}}\) |
| 4 | Simplify | \(\frac{\frac{4}{3} - \frac{3}{3}}{\frac{6}{3} - \frac{2}{3}} = \frac{\frac{1}{3}}{\frac{4}{3}}\) |
| 5 | Calculate final value | \(\frac{1}{3} \times \frac{3}{4} = \frac{1}{4}\) |
| Concept | Description | Relation |
|---|---|---|
| Tangent (\(\tan\theta\)) | Ratio of the side opposite to the angle to the side adjacent in a right triangle. | \(\tan\theta = \frac{\sin\theta}{\cos\theta}\) |
| Sine (\(\sin\theta\)) | Ratio of the side opposite to the angle to the hypotenuse in a right triangle. | |
| Cosine (\(\cos\theta\)) | Ratio of the side adjacent to the angle to the hypotenuse in a right triangle. |
When you are given a relationship like \(a \tan \theta = b\) or \(a \cot \theta = b\) and asked to evaluate an expression that is a ratio of linear combinations of \(\sin\theta\) and \(\cos\theta\), dividing the numerator and denominator by \(\cos\theta\) (for \(\tan\theta\)) or \(\sin\theta\) (for \(\cot\theta\)) is a very effective technique. This method works because it transforms the expression into a form that depends only on \(\tan\theta\) or \(\cot\theta\), whose value you can find from the given condition.
For example, an expression like \(\frac{a \sin\theta + b \cos\theta}{c \sin\theta + d \cos\theta}\) can be rewritten by dividing numerator and denominator by \(\cos\theta\) as \(\frac{a \tan\theta + b}{c \tan\theta + d}\), provided \(\cos\theta \ne 0\). Similarly, dividing by \(\sin\theta\) gives \(\frac{a + b \cot\theta}{c + d \cot\theta}\), provided \(\sin\theta \ne 0\).
This technique is useful in many trigonometry problems and helps simplify complex expressions quickly.
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