Simplify (x - y + z) 2- (x - y - z) 2.
4xz - 4yz
The problem asks us to simplify the expression $$(x - y + z)^2 - (x - y - z)^2$$. This expression has the form $$a^2 - b^2$$, which is a difference of squares. We can use the algebraic identity: $$a^2 - b^2 = (a + b)(a - b)$$.
Let's identify 'a' and 'b' in our expression:
Now, we need to find $$(a + b)$$ and $$(a - b)$$.
$$(a + b) = (x - y + z) + (x - y - z)$$
Remove the parentheses:
$$(a + b) = x - y + z + x - y - z$$
Combine like terms ($$x$$, $$y$$, and $$z$$ terms):
$$(a + b) = (x + x) + (-y - y) + (z - z)$$
$$(a + b) = 2x - 2y + 0$$
So, $$(a + b) = 2x - 2y$$.
$$(a - b) = (x - y + z) - (x - y - z)$$
Remove the parentheses. Remember to distribute the negative sign to each term inside the second set of parentheses:
$$(a - b) = x - y + z - x + y + z$$
Combine like terms ($$x$$, $$y$$, and $$z$$ terms):
$$(a - b) = (x - x) + (-y + y) + (z + z)$$
$$(a - b) = 0 + 0 + 2z$$
So, $$(a - b) = 2z$$.
Now, we multiply the results from Step 1 and Step 2:
$$(a + b)(a - b) = (2x - 2y)(2z)$$
Distribute $$2z$$ to each term inside the first parentheses:
$$(2x - 2y)(2z) = (2x)(2z) - (2y)(2z)$$
Perform the multiplication:
$$(2x)(2z) - (2y)(2z) = 4xz - 4yz$$
The simplified form of the expression $$(x - y + z)^2 - (x - y - z)^2$$ is $$4xz - 4yz$$.
Let's compare this result with the given options:
Our simplified expression, $$4xz - 4yz$$, matches Option 4.
Review of the key steps involved in simplifying expressions like this:
| Concept | Description | Formula/Method |
|---|---|---|
| Difference of Squares | A binomial of the form $$a^2 - b^2$$ | $$a^2 - b^2 = (a+b)(a-b)$$ |
| Identifying 'a' and 'b' | Recognizing the terms being squared | In $$(X)^2 - (Y)^2$$, $$a=X$$, $$b=Y$$ |
| Combining Like Terms | Adding or subtracting terms that have the same variables raised to the same power | e.g., $$2x + 3x = 5x$$, $$5y - 2y = 3y$$ |
| Distributive Property | Multiplying a term outside parentheses by each term inside | $$k(m + n) = km + kn$$ |
Algebraic identities are equations that are true for all values of the variables involved. The difference of squares is one common identity. Others include:
Using these identities can significantly simplify complex algebraic expressions and equations. In this specific problem, recognizing the difference of squares form made the simplification much faster than expanding each squared trinomial separately.
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